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egoroff_w [7]
3 years ago
10

When an atom of iron loses all of its 4s electrons and one of its 3d electrons, what is its charge?

Chemistry
1 answer:
icang [17]3 years ago
5 0
There are two electrons in 4s and 6 in 3d. When you lose 3 electrons, you will be left with an ion of 3+ charge!
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1. Compare and contrast the characteristics of metals and nonmetals.
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Answer:

1.Metals

These are very hard except sodium

These are malleable and ductile  pieces

These are shiny

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These are soft except diamond

These are brittle and can break down into pieces

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2. The electrochemical series helps to pick out substances that are good oxidizing agents and those which are good reducing agents.In an electrochemical series the species which are placed above hydrogen are more difficult to be reduced and their standard reduction potential values are negative.

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3 years ago
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Find the kinetic energy of the horse using KE=1/2 mv².
Dmitry [639]
KE=6,250Joules
You plug in your given numbers and remember to square 5 because that’s the speed
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Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at
valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100  - x  

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,  

121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042

120.9038x+122.9042\left(100-x\right)=12176.01

Solving for x, we get that:

x = 57.2 %

<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>

<u>percentage abundance of 123 Sb is = 100 - 57.2 %  = 42.8 %</u>

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What groups are Cl and F in
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Explanation:

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