<u>Answer:</u> The products of the given chemical equation are 
<u>Explanation:</u>
Protonation equation is defined as the equation in which protons get added in the substance.
The chemical equation for the protonation of carbonate ion in the presence of water follows:

By Stoichiometry of the reaction:
1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion
Hence, the products of the given chemical equation are 
1. minimize
2. not buy the insurance
3. too expensive in relation to the value of his vehicle
Answer:
The answer is
<h2>112.912 kPa</h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is

Since we are finding the new pressure

404.6 kPa = 404600 Pa
From the question we have

We have the final answer as
<h3>112.912 kPa</h3>
Hope this helps you
Hello!
The reaction that the graph represents is
A. Exothermic because Hrxn=-167 kJTo calculate Hrxn we apply the following equation:

Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is
lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction
releases energy in the form of heat and that the reaction is
exothermic.
Have a nice day!