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trapecia [35]
2 years ago
8

Which of the following observations indicates that an object is falling at terminal velocity?

Chemistry
1 answer:
spayn [35]2 years ago
7 0
I believe that's is answer C because your ask about and increasment on the velocity in this observation
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Summarize the weather conditions related to a cold front. Remember to include all data collected on cold fronts in this activity
svp [43]

Answer: Many fronts cause weather events such as rain, thunderstorms, gusty winds and  A weather front is a transition zone between two different air masses at the  Lifted warm air ahead of the front produces cumulus or cumulonimbus clouds

Explanation:

Hope this was helpful

5 0
2 years ago
Which of the following oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation
Murljashka [212]

Answer: Option (B) is the correct answer.

Explanation:

When a fatty acid contains high number of double bonds then its unsaturation will also be high and hence, it will consume greater number of equivalents of hydrogen.

In corn oil, there are no unsaturated sites are present.

In olive oil, there is one unsaturated site with majority of oleic acid. In olive oil, there are more than 70% of total unsaturated oils.

In lard oil, there are around 60% of unsaturated oils.

In herring oil, there are highest number of saturated fatty acids and lowest polyunsaturated acids.

Thus, we can conclude that out of the given options, olive oils would consume the greatest number of equivalents of hydrogen when subject to catalytic hydrogenation.

5 0
3 years ago
a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re
Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Given : 59.4 g of H_2SO_4 in 100 g of solution  

moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

Volume of solution =\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml

Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

M_2\text{ and }V_2 are the molarity and volume of dilute acid which is H_2SO_4

We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

Putting values in above equation, we get:

11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0
3 years ago
Which describes the path of energy that a gas powered car uses to drive along a road?
harkovskaia [24]

Answer:

mechanical energy to electrical energy to light energy

4 0
3 years ago
What does cellular respiration do?
Anton [14]
I believe the answer is A the 1st one
7 0
2 years ago
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