Things an animal does to survive are called behavioral adaptations. The correct option is c.
<h3>What is behavioral adaptation?</h3>
The adaptation of behavioral and physical characters that help to survive them.
For example, hibernating during winter, migration, etc. There are two types of behavioral adaptation, learned and instinctive.
Thus, the correct options are c: behavioral adaptations.
Learn more about behavioral adaptation
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For the reaction of weak acid:
The Henderson-hasselbalch equation is:
![pH = pk_a+ log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%20pH%20%3D%20pk_a%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20)
The concentration ratio at 
is:
![pH = pk_1+ log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%20pH%20%3D%20pk_1%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20)
Substituting the values:
![3.2 = 4.1 + log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%203.2%20%3D%204.1%20%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20)
![log \frac{[A^{-}]}{[HA]} = - 0.9](https://tex.z-dn.net/?f=%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20%3D%20-%200.9%20%20)
![\frac{[A^{-}]}{[HA]} = 0.126](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20%3D%200.126%20%20)
Now, for calculating the pk_2 value:
![pH = pk_2+ log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%20pH%20%3D%20pk_2%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D%20%20)
Thus, .
The Kelvin Scale is used, so the answer is temperature :)
Answer: -
First Ionization energy IE 1 for element X = 801
Here X is told to be in the third period.
So principal quantum number n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom. Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
Answer:
of the reaction is 1.7 kJ/mol.
Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.
Explanation:
The synthesis of acetyl CoA is as follows.
Form the given data,
Total the above two steps we get,
Therefore, of the reaction is 1.7 kJ/mol.
According to the Lechatelier's principle, a system at equilibrium always shows a tendency to regain the state of equilibrium., if equilibrium disturbed by an external factor only.
The enzyme inorganic pyrophosphotase catalyze the reaction.
The enzyme removes the ppi , one of the product in acetyl -CoA reaction.
This would disturb the equilibrium therefore, system try to regain the state of equilibrium. And the equilibrium shifted to the right side.
Therefore, Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.
