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2 years ago

Please help fast it would mean a lot please

Mathematics

1 answer:

Elan Coil [88]2 years ago

8 0

whats the question? ill help you out i just wanna Answer the right question

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Use the following data set to answer numbers 1 - 4.

alukav5142 [94]

Answer:

1. 13+18+13+14+13+16+14+21+13

= 145/9

=16.11

2. Range =145

3. Mode =13

4. Median =14

Step-by-step explanation:

6 0

1 year ago

The price of milk increased by 8 percent.If the original price is R10,84,what is the new price? step by step explanation

antiseptic1488 [7]

Answer:

If the price of a product decreases from $10 to $8, leading to an increase in quantity demanded from 40 to 60 units.

Step-by-step explanation:

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2 years ago

Which of the following is an integer?<br> 10.5<br> -9<br> XandY<br> 1/2

elena-14-01-66 [18.8K]

Answer:

-9

Step-by-step explanation:

an integer is a whole number!

4 0

2 years ago

Read 2 more answers

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

2 years ago

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Can you please help !!!

allsm [11]

Answer:

19) x=-3, 20) a=1, 21) b=3, 22) x=8

Step-by-step explanation:

hope that helps, those are the answeres to each question. :)))

8 0

3 years ago

Read 2 more answers