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KiRa [710]
3 years ago
14

Please help fast it would mean a lot please

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0

whats the question? ill help you out i just wanna Answer the right question

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Mila has biked 10 miles in 1.5 hours if Mila continues at the same rate,how many miles will she bike in 3 and a 1/2 hours?
Viefleur [7K]

Mike biked 10 miles in 1.5 hours. Mila bikes at the same rate too.

Therefore, she will bike x miles in 3.5 hours

(10/1.5) = (x/3.5)

You cross multiply

1.5x = 10 x 3.5

1.5x = 35

x = 35/1.5

x = 23 miles (approximately)

I hope this helps

6 0
3 years ago
Solve in any method. Help please
Komok [63]

Answer:

what exactly do yo need

Step-by-step explanation:

7 0
3 years ago
Never mind. I meant these problems. Please find the mean, median, and mode.
Sergio [31]
Median mean to find the center of the data
8 0
3 years ago
How do I do this problem with solution by elimination?<br> 2x+y=3<br> -2x+5y=-9
ddd [48]

Answer:

(2, -1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

2x + y = 3

-2x + 5y = -9

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Elimination</em>

  1. Combine equations:                    6y = -6
  2. Divide 6 on both sides:               y = -1

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define equation:                    2x + y = 3
  2. Substitute in <em>y</em>:                       2x - 1 = 3
  3. Isolate <em>y</em> term:                        2x = 4
  4. Isolate <em>y</em>:                                 x = 2
7 0
3 years ago
5
xz_007 [3.2K]
It should be 3.5 if im correct
4 0
2 years ago
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