24 knots is the maximum wind velocity for a 30 crosswind if the maximum crosswind component for the airplane is 12 knots.
What is crosswind component?
Although you should always prepare to land the aircraft into the wind, in practice the wind only occasionally blows directly down the runway. You will typically be landing with at least a small amount of crosswind. There is a limit to how much direct crosswind an airplane can land in. Only a portion of the wind is operating as a direct crosswind when it is blowing at a shallow (acute) angle to the runway.
The following are the variables needed to solve for the crosswind component:
Runway and wind direction
Wind speed
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Explanation:
In the picture, I hope that it's a clear solution.
Answer:
Heat transfer in the process is -19.6 kJ
Work done in the process is - 28 kJ
Explanation:
As we know that the process equation is given as
now we know that
now from above equation we have
now work done in this process is given as
here we know N = 1.1
so we have
Now we have
now we have
so we have
A body of mass 2kg is at rest. A force of 20N makes it move with a velocity of 5m/s, the impulse of the body would be 10 Kgm/s
<h3>What is impulse?</h3>
The product of the average applied force and the time for which it is exerted is known as an impulse. The unit for the impulse of force is the same as that of momentum which is kg*m/s
The mathematical relation for impulse is
Impulse = F * Δt =change in momentum
As given in the problem body of mass of 2 kg is at rest. A force of 20N makes it move with a velocity of 5m/s
Change in the momentum of the body
Δm = m(v₂-v₁)
As the body was initially at rest v₁ =0
Δm = 2×5
Δm = 10 Kgm/s
As we know that change in the momentum represents the impulse of the force
Thus, the impulse of the body would be 10 Kgm/s
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