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Airida [17]
2 years ago
13

What is the maximum wind velocity for a 30 crosswind if the maximum crosswind component for the airplane is 12 knots?

Physics
1 answer:
Ray Of Light [21]2 years ago
6 0

24 knots is the maximum wind velocity for a 30 crosswind if the maximum crosswind component for the airplane is 12 knots.

What is crosswind component?

Although you should always prepare to land the aircraft into the wind, in practice the wind only occasionally blows directly down the runway. You will typically be landing with at least a small amount of crosswind. There is a limit to how much direct crosswind an airplane can land in. Only a portion of the wind is operating as a direct crosswind when it is blowing at a shallow (acute) angle to the runway.

The following are the variables needed to solve for the crosswind component:

Runway and wind direction

Wind speed

To learn more about crosswind component click the given link

brainly.com/question/27960498

#SPJ4

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The primary purpose of a mirror is to _________ light rays.
Effectus [21]
a. reflect (I found this using prior knowledge and process of illumination it can't be absorb cuz you wouldn't see anything it can't be refract because it doesn't reverse the image and it isn't transmit )
8 0
4 years ago
Review 1: A plane is located x = 40 miles (horizontally) away from an airport at an altitude of h miles. Radar at the airport de
-Dominant- [34]

Explanation:

Let h is the height of the plane above ground. x is the horizontal distance between the ground and the airport. Let s(t) is the distance between the plane and the airport. So,

s(t)^2={h^2+x^2}...........(1)

Given, h = 4, x = 40 and s(t) = -20 mph

Differentiate equation (1) wrt t

2s(t)s'(t)=2x(t)x'(t)

x'(t)=\dfrac{s(t)s'(t)}{x(t)}

When x = 40, s(t)=\sqrt{40^2+4^2}=40.19\ m

x'(t)=\dfrac{-240s(t)}{x(t)}

x'(t)=\dfrac{-240\times 40.19}{40}

x'(t)=-241.14\ m/s

So, the speed of the airplane is 241.14  m/s. Hence, this is the required solution.

8 0
4 years ago
Which of these help create radio waves?
inysia [295]
The one that help create radio waves is :
Changing electric and magnetic fields applied at right angles

Radio waves are transverse wave, which means  that the oscillations occurring perpendicular to the direction of energy transfer

hope this helps
3 0
3 years ago
What best describes the direction of the electric field on a spherical equipotential surface?
Alla [95]

Answer:

Perpendicular to the surface

Explanation:

- Electric field lines represent the direction of the electric field. The electric field lines also correspond to the direction along which the gradient of the electric potential is maximum.

- Equipotentials are lines or surfaces along which the electric potential is constant: the electric potential does not change moving along an equipotential surface.

Given the two definitions, equipotential lines are always perpendicular to the electric field lines. Therefore, in this problem, the direction of the electric field is perpendicular to the spherical equipotential surface.

4 0
4 years ago
A car with a mass of 710 kg is traveling at 37 km/hr. It accelerates to a speed of 120 km/hr in 12.6 seconds. What is the net fo
guajiro [1.7K]

Answer: The net force acting on the car 1,299.3 N.

Explanation:

Mass of the car = 710 kg

Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s (1km\h=\frac{5}{18} m/s)

Final velocity of the car,v = 120 km/h = 33.33 m/s

time taken b y car = 12.6 sec

v-u=at

33.33m/s-10.27m/s=23.06 m/s=a(12.6 sec)

a = 1.83 m/s^2

Force=mass\times acceleration

Force=710 kg\times 1.83 m/s^2

Force=1,299.3 N

The net force acting on the car 1,299.3 N.

8 0
3 years ago
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