Answer:
c
Explanation:
Hello!
To solve this problem we need to know the velocity and position of the train as a fucntion of time and acceleration. Since the train started from rest, these are the formulas:
v = at
x = (1/2)a*t^2
From the first equation we can know the time as a division between the velocity and the acceleration:
t = (v/a)
Replacing this value in the second equation we get:
x = (1/2)*a*(v/a)^2 = v^2/(2*a)
Solving for a:
a = (1/2)*(v^2/x)
Now, we know that when x=5.6km =5600 m, the velocity of the train is v =42 m/s
Therefore:
a = (1/2)*(42^2/5600) m/s^2 = 0.1575 m/s^2
So, the answer is c, the acceleration of the train during the first 5.6 km is colse to 0.16m/S^2
Answer:
The answer is A. Cementing...
Explanation:
hope this helps
Meters for mass kilograms for volume cubic meters for density kilograms per cubic meter
Answer: 15 mph east
Explanation: Since the bicycle went east for 30 miles, in 2 hours. You divide 30 by how many hours which is 2. So, the solution is 15.