Answer:
a)43.8 m/s
b)103.54 m/s
Explanation:
Work energy theorem
Δ Δ
a) In this part v1=0 and h2=0
=0
b) in this part v2=0, h1= 0, and h2= 545m
A car is travelling at a steady velocity of 28 m/s. It accelerates for 6 seconds to overtake a van. Its new velocity is 32.5 m/s
. Calculate the acceleration of the car.
1 answer:
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Answer:
1) The time it takes the diver to move off the end of the diving board to the pool surface, , is approximately 1.392 seconds
2) The horizontal distance from the edge of the pool to where the diver enters the water, , is approximately 5.76 meters
Explanation:
1) The given parameters are;
The height of the diving board above the pool's surface, h = 9.5 m
The length by which the diving board over hangs the pool L = 2 m
The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s
Taking = The time it takes the diver to move off the end of the diving board to the pool surface
Therefore, we have from the equation of free fall;
h = 1/2 × g × ²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
9.5 = 1/2 × 9.81 × ²
= √(9.5/(1/2 × 9.81)) ≈ 1.392 s
The time it takes the diver to move off the end of the diving board to the pool surface = ≈ 1.392 s
2) The horizontal distance, , in meters from the edge of the pool to where the diver enters the water is given as follows;
= L + v₀ ×
= 2 + 2.7× 1.392 ≈ 5.76 m
∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.