2 years ago

Elastic and inelastic collisions

1 answer:

5 0

Explanation:

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.

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What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 49 k

Molodets [167]

Answer:

$\dfrac{I_1}{I_2}=12.25$

Explanation:

$r_1$ = 14 km

$r_2$ = 49 km

Intensity of a wave is inversely proportional to distance

$I\propto \dfrac{1}{r^2}$

So,

$\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{49^2}{14^2}\\\Rightarrow \dfrac{I_1}{I_2}=12.25$

The ratio of the intensities is $\dfrac{I_1}{I_2}=12.25$

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2 years ago

On his honeymoon, James Joule attempted to explore the relationships between various forms of energy by measuring the rise of te

Marizza181 [45]

Answer:

The maximum temperature rise = 0.047 °C

Explanation:

Potential Energy, P = mgh

Energy transfered, Q=mcΔT

Potential energy = Energy transfered

mgh = mcΔT

gh = cΔT

ΔT = gh/c

ΔT = (9.81 * 20) / 4186

ΔT = 0.047 °C

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3 years ago

Suppose the current in a conductor decreases exponentially with time according to the equation I(t) = I0e-t/τ, where I0 is the i

ELEN [110]

Answer:

Pls see attached file

Explanation:

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3 years ago

The tires on your truck have 0.35 m radius. In a straight line, you drive 2600 m. What is the angular displacement of the tire,

Travka [436]

1) In a circular motion, the angular displacement $\theta$ is given by
$\theta = \frac{S}{r}$
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire: $S=2600 m$ . Using the information about the radius, $r=0.35 m$ , we find the total angular displacement:
$\theta = \frac{2600 m}{0.35 m} =7428 rad$

2) If we put larger tires, with radius $r=0.60 m$ , the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
$\theta = \frac{2600 m}{0.60 m}=4333 rad$

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3 years ago

Plans used for work that has to do with construction in or around earth are called

attashe74 [19]

Plans used for work that has to do with construction in or around Earth are called, “Civil Plans.”

Hope this helped!

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3 years ago