Answer:
The quadratic equation form is x² - 9 x + 14 = 0
Step-by-step explanation:
Given in the question as ,
The solution of quadratic equation are x = 2 and x = 7
The constant K is a non-zero number
Now , let the quadratic equation be , ax² + bx + c = 0
And sum of roots = 
product of roots = 
So, 2 + 7 =
Or, 2 × 7 =
I.e = 9 , = 14
Or, b = - 9 a And c = 14 a
Put this value of b and c in standard form of quadratic equation
I.e ax² + bx + c = 0
Or, ax² - 9 ax + 14 a = 0
Or , a ( x² - 9 x + 14 ) = 0
∴ a = 0 And x² - 9 x + 14 = 0
Hence , The quadratic equation form is x² - 9 x + 14 = 0 Answer
Answer:
y=1
Step-by-step explanation:
because 2×1=2 and when you add 4 to it you will get 6
I believe it could be the third answer.
Answer: ( x + 1)² + (y - 4)² = 16
Explanation:
1) The given equation, ( x - 2)² + (y + 1)² = 16, represents a circumference with center (2,-1) and radius √16 = 4.
1) The translation will not modify the radius of the circunference, siince translations are rigid transformations.
2) The translation 3 units to the left and 5 units upward certainly will move the center of the circunference.
This is how:
(x,y) → (x - 3, y + 5)
(2, -1) → (2 - 3, - 1 + 5) = (- 1, 4)
3) Then, keeping the same radius and being the center (-1,4), the equation of the circumference after the translation will be:
( x + 1)² + (y - 4)² = 16 ← answer
