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dolphi86 [110]
3 years ago
9

5. Find the product of p(x) and q(x) if p(x) = 2x+7 and q(x) = 4x-9

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer:

p(x), q(x), and their product are all polynomials.

p(x) · q(x) = 6x² + 10x - 63

Step-by-step explanation:

First of all P(x) and q(x) are polynomials because polynomials refer to any sum, difference, or product of a collection of algebraic terms. The word polynomials is general. P(x) and q(x) are polynomials but more specifically they are binomials since they only have two terms. Their product is a polynomial as well, but more specifically its a trinomial because it has three terms.

<em>process of multiplying</em>

Using the distributive property (or foil method) when multiplying p(x) and q(x) you would first get the expression 6x² - 18x + 28x - 63. From here you would combine "like terms". This would give you your final answer of

6x² + 10x - 63. Sorry, I couldn't help you with the D question but I hope this helps ;)

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the hypotenuse of the right angled triangle is 6cm more than twice the shortest side. if the third side is 2 cm less than the hy
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Answer:

Let the base be p

Hypotenuse = 2p +6

Perpendicular = 2p + 4

By Pythagoras theoram

(2p+6)^2 = (2p+4)^2 +p^2

=> 4p^2 +36 + 24p = 4p^2 + 16 +16p +p^2

=> 36+ 24p = p^2 + 16p + 16

=> p^2 - 8p - 20 = 0

=> p^2 - 10p +2p - 20 = 0

=> p(p-10) +2(p-10) = 0

=> (p-10)(p+2) = 0

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So,

p = 10

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Plz help ASAP. Need help on this
nexus9112 [7]

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Hope it helps!

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