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4 years ago

5. Find the product of p(x) and q(x) if p(x) = 2x+7 and q(x) = 4x-9

Mathematics

1 answer:

stepan [7]4 years ago

3 0

Answer:

p(x), q(x), and their product are all polynomials.

p(x) · q(x) = 6x² + 10x - 63

Step-by-step explanation:

First of all P(x) and q(x) are polynomials because polynomials refer to any sum, difference, or product of a collection of algebraic terms. The word polynomials is general. P(x) and q(x) are polynomials but more specifically they are binomials since they only have two terms. Their product is a polynomial as well, but more specifically its a trinomial because it has three terms.

process of multiplying

Using the distributive property (or foil method) when multiplying p(x) and q(x) you would first get the expression 6x² - 18x + 28x - 63. From here you would combine "like terms". This would give you your final answer of

6x² + 10x - 63. Sorry, I couldn't help you with the D question but I hope this helps ;)

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Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

Given the equation 4x − 26 = 2x − 4, which order of operations completely solves for x?

scoray [572]

4x - 26 = 2x - 4....subtract 2x from both sides
4x - 2x - 26 = -4...add 26 to both sides
4x - 2x = -4 + 26...combine terms
2x = 22...divide both sides by 2
x = 22/2 = 11

OR
4x - 26 = 2x - 4.....subtract 4x from both sides
-26 = 2x - 4x - 4....add 4 to both sides
-26 + 4 = 2x - 4x...combine terms
-22 = -2x....divide both sides by -2
-22/-2 = x
11 = x

6 0

4 years ago

In the diagram below, AB is parallel to CD. What is the value of x?

garik1379 [7]

The correct answer is: Option (D) x = 72°

Explanation:

When two lines are crossed by another line, the angles in matching corners are called corresponding angles. When the two lines are parallel, the corresponding angles are equal.

Here in this case, the two lines are "AB" and "CD", and both are parallel and are crossed by the line; therefore, the corresponding angles will be the same.

Since the first corresponding angle is 72°, the second angle x will be 72° as well. The correct answer is: x = 72° Option (D).

8 0

3 years ago

Read 2 more answers

PLEASE HELP THIS IS DUE ASAP!!!!!

just olya [345]

Answer:

101

Step-by-step explanation:

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3 years ago

What x-value makes the set of ratios equivalent? 2 : 3 = 6 : x 4 : 7 = x : 42 2x : 48 = 3 : 12 12 : 15 = x : 20

Oliga [24]

Answer:

2 : 3 = 6 : x (9)

3 : 12 = 2x : 48 (6)

12 : 15 = x : 20 (16)

4 : 7 = x : 42 (24)

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3 years ago