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dolphi86 [110]
3 years ago
9

5. Find the product of p(x) and q(x) if p(x) = 2x+7 and q(x) = 4x-9

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer:

p(x), q(x), and their product are all polynomials.

p(x) · q(x) = 6x² + 10x - 63

Step-by-step explanation:

First of all P(x) and q(x) are polynomials because polynomials refer to any sum, difference, or product of a collection of algebraic terms. The word polynomials is general. P(x) and q(x) are polynomials but more specifically they are binomials since they only have two terms. Their product is a polynomial as well, but more specifically its a trinomial because it has three terms.

<em>process of multiplying</em>

Using the distributive property (or foil method) when multiplying p(x) and q(x) you would first get the expression 6x² - 18x + 28x - 63. From here you would combine "like terms". This would give you your final answer of

6x² + 10x - 63. Sorry, I couldn't help you with the D question but I hope this helps ;)

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If ABC and EDC are similar, what is the value<br> of x?<br> A
abruzzese [7]

Answer:

x = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

BC/DC = EC/AC , substitute values

3x×5/32 - 5x-5/56 ( cross- multiply )

56(3x - 5) = 32(5x - 5) ← distribute and simplify both sides

168x - 280 = 160x - 160 ( subtract 160x from both sides )

8x - 280 = - 160 ( add 280 to both sides )

8x = 120 ( divide both sides by 8 )

x = 15

3 0
3 years ago
Please Help me ASAP
pychu [463]

Answer:

it's 6

Step-by-step explanation:

B=7 and D=13, so 13-7= 6

3 0
2 years ago
Find the rate of change of the function h(x) = 2 x on the interval 2 ≤ x ≤ 4
dangina [55]
For a linear function, the instantaneous rate of change is everywhere equal to the slope. Thus the rate of change of the function h(x)=2x on the interval 2≤x≤4
The rate of change of the function given will equal to its slope, thus;
slope,m=(y-1-y)/(x_1-x)
=(2*4-2*2)/(4-2)
=(8-4)/2
=4/2
=2

the answer is 2 
7 0
3 years ago
The standard form of the equation of a parabola is y= x2 - 8x + 29.
fomenos

Answer:

A

Step-by-step explanation:

Put brackets around the first two tems.

y = (x^2 - 8x) + 29

Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.

1/2 (- 8) = - 4

(- 4)^2 = 16

y = (x^2 - 8x + 16) + 29

Subtract 16 outside the brackets.

y = (x^2 - 8x + 16) + 29 - 16  

Do the subtraction

y = (x^2 - 8x + 16) + 13

Represent what is inside the brackets as a square.

y = ( x - 4)^2 + 13

The answer is A

7 0
3 years ago
The diagram shows a straight line ABCD.
Nady [450]

Answer:

B (0, 285 ) , C (380, 0 )

Step-by-step explanation:

the first step is to obtain the equation of the line in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = A(- 260, 480 ) and (x₂, y₂ ) = D (620, - 180 )

m = \frac{-180-480}{620-(-260)} = \frac{-660}{620+260} = \frac{-660}{880} = - \frac{66}{88} = - 0.75 , then

y = - 0.75x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equatio

using (620, - 180 ) , then

- 180 = - 465 + c ⇒ c = - 180 + 465 = 285

So y- intercept is B (0, 285 )

y = - 0.75x + 285 ← equation of line

to find the x- intercept , let y = 0 in the equation and solve for x

0 = - 0.75 + 285 ( subtract 285 from both sides )

- 285 = - 0.75x ( divide both sides by - 0.75 )

380 = x

x- intercept is C (380, 0 )

4 0
2 years ago
Read 2 more answers
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