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Delvig [45]
3 years ago
8

Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, QS= Q'S' = 5 units, and angles Q and Q' are bot

h 90 degrees. Which theorem below would prove the two triangles are congruent?
Mathematics
2 answers:
const2013 [10]3 years ago
5 0
It would be ASA(angle side angle)

if 2 angles and an included side are congruent, then the two triangles are congruent.
meriva3 years ago
3 0

Answer:

HL Theorem

Step-by-step explanation:

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I need help with 2 questions in distributive property
Snezhnost [94]

Answer:

i don't know

Step-by-step explanation:

4 0
4 years ago
What is bigger?? 2.5 feet or 32 inches?
Pie


32 in. because 2.5 feet is only 30 in


6 0
3 years ago
Read 2 more answers
Monica asked her friends to buy a charity raffle ticket for $3. All but 4 of her friends bought a ticket, and she raised $18. Ho
Dafna11 [192]

Answer:

She asked 10 friends to buy tickets.

Step-by-step explanation:

If each ticket sells for 3 dollars, you can get the amount of people that bought the tickets by taking the amount earned divided by the price of the ticket.

$18 / $3 = 6

If 6 friends bought tickets and 4 friends did not, add the two together and you will get how much people Monica asked.

6 + 4 = 10

She asked 10 friends to buy tickets.

5 0
4 years ago
Read 2 more answers
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Can someone help me solve this question? It’s similar to the previous ones! Thank you!
luda_lava [24]

Answer:

\boxed{\sf \ \ \ (-2x+-9)(1x+3)=-2x^2-15x-27 \ \ \ }

the coefficient c is -27

Step-by-step explanation:

hello

(-2x+-9)(1x+3)=(-2x-9)(x+3)=-2x(x+3)-9(x+3)=-2x^2-6x-9x-27\\=-2x^2-15x-27

hope this helps

8 0
4 years ago
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