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agasfer [191]
3 years ago
15

A 15 g bullet is fired horizontally into a block of wood with a mass of 2.5 kg and embedded in the block. initially the block of

wood hangs vertically and the impact cause the block to swing so that it its center of mass rises 15 cm. find the velocity of the bullet just before the impact.
Physics
1 answer:
Vlada [557]3 years ago
3 0
Some random math hard to explain 229m/s

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Distinguish between basic and derived units
alex41 [277]

Answer:

Base units are defined units based on specific objects or events in the physical world. Derived units are defined by combining base units.

Base units are defined by a particular process of measuring a base quantity whereas derived units are defined as algebraic combinations of base units. For example, length is a base quantity in both SI and the English system, but the meter is a base unit in the SI system only.

8 0
3 years ago
A trout was swimming in a river. The trout swam 7,000centimeters directly upstream at a constant velocity. It swam that distance
Mars2501 [29]

Answer:

10000

Explanation:

7 0
3 years ago
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How much physical activity do children and trens need?
saveliy_v [14]

Answer:

it should be 60 min at least 3 days a week

8 0
3 years ago
After a 0.320-kg rubber ball is dropped from a height of 19.0 m, it bounces off a concrete floor and rebounds to a height of 15.
GarryVolchara [31]

Answer:

Imp = 11.666\,\frac{kg\cdot m}{s}

Explanation:

Speed experimented by the ball before and after collision are determined by using Principle of Energy Conservation:

Before collision:

(0.32\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (19\,m) = \frac{1}{2}\cdot (0.320\,kg)\cdot v_{A}^{2}

v_{A} \approx 19.304\,\frac{m}{s}

After collision:

\frac{1}{2}\cdot (0.320\,kg)\cdot v_{B}^{2} = (0.32\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (15\,m)

v_{B} \approx 17.153\,\frac{m}{s}

The magnitude of the impulse delivered to the ball by the floor is calculated by the Impulse Theorem:

Imp = (0.32\,kg)\cdot [(17.153\,\frac{m}{s} )-(-19.304\,\frac{m}{s} )]

Imp = 11.666\,\frac{kg\cdot m}{s}

5 0
3 years ago
Read 2 more answers
If a person walks first 70 m in the direction 37° north of east, and then walks 82 m in the
timurjin [86]

Aster's final position from her initial position is 63 m approximately. She will head north west direction to return to her initial position

<h3>What is Displacement ?</h3>

Displacement is the distance travelled in a specific direction. It is a vector quantity.

Given that a person walks first 70 m in the direction 37° north of east, and then walks 82 m in the direction 20° south of east, and finally walks 28 m in the direction 30° west of north.

a) Let P be the Aster's final position from her initial position?

We can use bearing by using Cosine formula to solve this question.

P² = 70² + 82² - 2 × 70 × 82 cos 73

P² = 4900 + 6724 - 11480 cos 73

P² = 11624 - 3356.43

P² = 8267.57

P = √8267.57

P = 90.9 m

P = 90.9 - 28

P = 62.9 m

We can get the angle by using Sine rule

82/ sin Ф = 90.9 / sin 73

sin Ф = 0.8627

Ф = Sin^{-1} (0.8627)

Ф = 59.6°

Ф = 60°

b)  She will head north west direction to return to her initial position

Learn more about Displacement here: brainly.com/question/2109763

#SPJ1

3 0
1 year ago
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