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Jet001 [13]
3 years ago
7

A spaceship moves at a speed of 0.95 c away from the Earth. It shoots a star wars torpedo toward the Earthat a speed of 0.90 c r

elative to the ship. What is the velocity of the torpedo relative to the Earth? (The direction in which the spaceship move
Physics
1 answer:
wariber [46]3 years ago
5 0

Answer:

0.345 c

Explanation:

v_{se} = velocity of spaceship relative to earth = 0.95 c

v_{ts} = velocity of torpedo relative to spaceship = - 0.90 c

v_{te} = velocity of torpedo relative to earth

Velocity of torpedo relative to earth is given as

v_{te}=\frac{v_{se} + v_{ts}}{1 + \frac{v_{se}v_{ts}}{c^{2}}}

v_{te}=\frac{0.95c + (- 0.90 c)}{1 + \frac{(0.95 c)(- 0.90 c))}{c^{2}}}

v_{te} = 0.345 c

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Answer:

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Explanation:

It is given that,

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So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.

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