The answer is C because thats what the answer is so good luck in the class
Answer:
a) 
b) 
Explanation:
Given;
- depth of the water-tank,
- length of the pipe,
- inclination of the pipe from the horizontal,
a)
Now the effective vertical height of the water column from the free surface of the water to the bottom of the pipe at house:
Now the pressure due to effective water head:
where:
density of the liquid, here water
acceleration due to gravity
height of the liquid column
b)
Now the height of water corresponding to this pressure will be the same as the effective water head by the law of conservation of energy.
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Answer:
It only depends on the vertical component
Explanation:
Hello!
The horizontal component will tell you how much you travel in that direction.
You could have a large horizontal velocity, but if the vertical velocity is zero, you will never be out of the ground. Similarly, you could have a zero horizontal velocity, but if you have a non-zero vertical velocity you will be some time off the ground. This time can be calculated by two means, one is using the equation of motion (position as a function of time) and the other using the velocity as a fucntion of time.
For the former you must find the time when the position is zero.
Lets consider the origin of teh coordinate system at your feet
y(t) = vt - (1/2)gt^2
We are looking for a time t' for which y(t')=0
0 = vt' - (1/2)gt'^2
vt' = (1/2)gt'^2
The trivial solution is when t'=0 which is the initial position, however we are looking for t'≠0, therefore we can divide teh last equation by t'
v = (1/2)gt'
Solving for t'
t' = (2v/g)
