Question

A 50 kg bobsled slides down an ice track starting (at zero initial speed) from the top of a(n) 184 m high hill. The acceleration of gravity is 9.8 m/s 2 . Neglect friction and air resistance and determine the bobsled’s speed at the bottom of the hill. Answer in units of m/s

Answer 1

Answer:

Explanation:

Given

mass of ice $m=50\ kg$

Height of hill $h=184\ m$

Neglecting air resistance

As resistance is absent so Energy at top of hill and at the bottom hill is conserved.

Energy at top is equal to Potential Energy

$E_T=mgh=50\times 9.8\times 184$

Energy at bottom is equal to kinetic energy at bottom

$E_B=\frac{1}{2}mv^2$

$E_T=E_B$

$50\times 9.8\times 184=\frac{1}{2}\times 50\times v^2$

$v=\sqrt{2\times 9.8\times 184}$

$v=60.05\ m/s$