Yes you would do a. y =(5) -4 b. y=50-2(5)^2 and c. y= 2^5
By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>
In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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in³ are the units associated with volume, V. Arletha's measurement could represent volume.
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Area, B, would have units of in². Height, h, would have units of in.
Well I know that c. goes with I. just because I saw so many x^3 graphs.
For a. the parent function is x^2, so 0.5x^2 should look about the same as x^2, so the answer is VI.
Answer:
Step-by-step explanation:
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