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OLga [1]
3 years ago
8

Please help I need by tomorrow

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0
#4 is +2 try the rest
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45x + 10
igor_vitrenko [27]
D because when you distribute the 5 into both numbers your product becomes 45x + 10
4 0
3 years ago
Read 2 more answers
What is the value of x in the equation below?
sveta [45]

Answer: C

Step-by-step explanation:

1+2e^x+1=9

2e^x+1=9-1

e^x+1= 8/2

e^x+1 = 4

Here we can applicate the Ln:

ln e^x+1 = ln 4

Applicating the log property for exponent:

(x+1).ln e = ln 4

Ln e = 1, so:

x+1 = ln 4

x = ln 4-1

7 0
3 years ago
Triangle ABC and DEF are right triangles, as shown. Triangle ABC is similar to triangle DEF. which ratios are equal to sin C?
Dafna11 [192]

Answer:

First option and Fourth option.

Step-by-step explanation:

To solve this exercise you need to use the following Trigonometric Identity:

sin\alpha=\frac{opposite}{hypotenuse}

In this case you know that:

\alpha =C

Since triangle ABC is similar to triangle DEF:

\angle C=\angle F

Let's begin with the triangle ABC.

You can identify that:

opposite=AB\\hypotenuse=AC

Then, substituing values, you get:

sinC=\frac{AB}{AC}

In triangle DEF, you know that:

opposite=DE\\hypotenuse=DF

So, substituing values, you get:

sinF=sinC=\frac{DE}{DF}

4 0
3 years ago
Find all solutions to the equation.<br><br> cos2x + 2 cos x + 1 = 0
yanalaym [24]
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.

So x = pi/2, pi/2 + pi = 3pi/2.

5 0
3 years ago
Please help asap…………
sineoko [7]

Answer: linear

Step-by-step explanation:

4 0
2 years ago
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