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Vaselesa [24]
3 years ago
11

An oil film (n = 1.48) of thickness 290 nm floating on water is illuminated with white light at normal incidence. What is the wa

velength of the dominant color in the reflected light? A. Blue (470 nm) B. Green (541 nm) C. Violet (404 nm) D. Yellow (572 nm)
Physics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

The correct option is  D

Explanation:

From the question we are told that

   The  refractive index of oil film is k =  1.48

   The  thickness is t =  290 \ nm  =  290*10^{-9} \ m

   

Generally for constructive interference

      2t  =  [m  + \frac{1}{2} ]*  \frac{\lambda}{k}

For reflection of a bright fringe m =  1

 =>   2 * (290*10^{-9})  =  [1  + \frac{1}{2} ]*  \frac{\lambda}{1.48}

=>     \lambda  =  5.723 *10^{-7} \  m

This wavelength fall in the range of a yellow light

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I Think The answer is a I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
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3 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has—— energy. Calculate
Slav-nsk [51]

Answer:

945 j

Explanation:

You have just given the ball kinetic energy, which is given by the following equation:

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A weight lifter lifts a dumbbell a certain height in 2.0 s, while a competitor does the same workin 1.0 s. Compared to the power
Aloiza [94]

Answer:

a. one-half as great

Explanation:

The power developed by the first lifter is one-half as great as that of the second person.

  Power is defined as the rate at which work is done;

          Power  = \frac{workdone}{time}

Since the two lifters do the same work at different time, let us estimate their power;

       P₁ = \frac{workdone}{2}                     P₂ = \frac{workdone }{1}

   We see that for P₁, power is half of the work done whereas in P₂ power is the same as the work done.

Therefore,

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Within which type of water body does water move the slowest?
lawyer [7]
It's D i'm pretty sure
6 0
3 years ago
Read 2 more answers
The atlas stone’s is a strong man competition where athletes have to load 5 stones of masses 100kg, 120kg, 140kg, 160kg and 180k
lyudmila [28]

Answer: 6250 joules

Explanation:

The work needed to lift an object of mass M by a height H is equal to:

w = M*g*H

where h = 10m/s^2

then the total work that he did is equal to the sum of the work for every stone:

W = (100kg*g*H) + (120kg*g*H) + (140kg*g*H) + (160kg*g*H) + (180kg*g*H)

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= (500kg)*g*H

and now we can repalce g by 10m/s^2 and H by 125cm

But you can notice that we have two different units of distance, so knowing that 100cm = 1m

we can write H =  125cm = (125/100) m = 1.25 m

Then we have:

H = 500kg*10m/s^2*1.25m = 6250 J

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3 years ago
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