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Vaselesa [24]
3 years ago
11

An oil film (n = 1.48) of thickness 290 nm floating on water is illuminated with white light at normal incidence. What is the wa

velength of the dominant color in the reflected light? A. Blue (470 nm) B. Green (541 nm) C. Violet (404 nm) D. Yellow (572 nm)
Physics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

The correct option is  D

Explanation:

From the question we are told that

   The  refractive index of oil film is k =  1.48

   The  thickness is t =  290 \ nm  =  290*10^{-9} \ m

   

Generally for constructive interference

      2t  =  [m  + \frac{1}{2} ]*  \frac{\lambda}{k}

For reflection of a bright fringe m =  1

 =>   2 * (290*10^{-9})  =  [1  + \frac{1}{2} ]*  \frac{\lambda}{1.48}

=>     \lambda  =  5.723 *10^{-7} \  m

This wavelength fall in the range of a yellow light

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the angle between r and the positive z axis.

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