Calculate the acceleration of a car that is maintaining a constant velocity of 1m/s
2 answers:
Answer:
Acceleration, a =0
Explanation:
If the velocity is constant, it means the acceleration of the object is equal to zero. Mathematically, the acceleration of an object is given by :
It is also defined as the change in speed per unit time. Its SI unit is . It is a vector quantity.
So, it is concluded that if a car is maintaining a constant velocity of 1 m/s, its acceleration is equal to zero. Hence, this is the required solution.
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Answer:
Time period of horizontal Oscillation = T = 2
As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.
Explanation:
Solution:
As we know that:
F = Kx
Here,
K = Spring constant
x = displacement.
First, they are displacing it with 6 cm from its rest position for which Time period of the oscillation is T = 2 seconds.
But next, they want to know the effect on the time period of the oscillation if the displacement x is doubled from 6cm to 12 cm.
First of all, let us see the equation of the time period of the oscillation.
We need to check, if time period does depend on the displacement or not.
As we know,
Time period of horizontal Oscillation = T = 2
As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.
Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.
Hence the Time period will remain same.