Next week your math teacher is giving a chapter test.

Mathematics

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

35-20= 15

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a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o

NemiM [27]

Answer:

Average = -1°C

Step-by-step explanation:

The data recorded is;

6, -7, -5, 5, -8, 3 (in °C)

Average = $\frac{6 - 7 - 5 + 5 - 8 + 3}{6}$ = -1°C

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3 years ago

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Solve by elimination -7x-20=-14 -2x+10y=-4

sweet-ann [11.9K]

Mark brainliest please mark

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3 years ago

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

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3 years ago

Two numbers have an absolute value of 16. Which of the two numbers is greater than 12

torisob [31]

The two numbers are l-16l and l16l. the one that is greater than 12 is l16l

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3 years ago

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How to find the mean of a data set with a missing value?

kotykmax [81]

<span>If you are given a mean and asked for one of the data values, you can still use the basic method for determining the mean, but work backwards. Generally we add up all the values and then divide by the number of values. In this case, working backwards, we multiply by the number of values (instead of dividing) and then subtract (instead of adding). You should be left with a data value from the set. </span>

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3 years ago