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3 years ago

Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. Write a word amd chemical equation for this reaction.

Chemistry

1 answer:

Varvara68 [4.7K]3 years ago

7 0

Answer: -

Magnesium reacts very slowly to form magnesium hydroxide and hydrogen gas. The balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

Explanation: -

Chemical symbol of magnesium = Mg

Chemical formula for magnesium hydroxide = Mg(OH)₂

Chemical formula for hydrogen gas = H₂

The other reactant with Mg must be water H₂O.

Thus the balanced chemical equation for the reaction is

Mg + 2H₂O → Mg(OH)₂ + H₂

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Exam 3 Material

Homework Page Without Visible Answers

This page has all of the required homework for the material covered in the third exam of the first semester of General Chemistry. The textbook associated with this homework is CHEMISTRY The Central Science by Brown, LeMay, et.al. The last edition I required students to buy was the 12th edition (CHEMISTRY The Central Science, 12th ed. by Brown, LeMay, Bursten, Murphy and Woodward), but any edition of this text will do for this course.

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3.2 moles of H3PO4 to grams

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313, 6grams of H3PO4

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3 years ago

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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