Answer:
0.2g
Explanation:
All radiodecay follows the 1st order decay equation
A = A₀e^-kt
A => Activity at time (t)
A₀ => Initial Activity at time = 0
k => decay constant for isotope
T => time in units that match the decay constant
Half-Life Equation => kt(½) = 0.693 => k = 0.693/34 min = 0.0204min¹
A = A₀e^-kt = (26g)e^-(0.0204/min)(238min) = (26g)(0.0078) = 0.203g ~ 0.2g (1 sig fig).
Answer:
1.38 atm
Explanation:
Partial pressure of a gas = total pressure × mole fraction of that gas.
Mole fraction of a gas is moles of a gas ÷ total moles of all gases.
The combustion of Methane produces CO₂ and water;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
According to balance equation,
1 Mole of CH₄ on combustion give = 2 Moles of H₂O
So,
2 Moles of CH₄ will produce = X Moles of H₂O
Solving for X,
X = (2 Moles × 2 Moles) ÷ 1 Mole
X = 4 Moles
Result:
4 Moles of H₂O is produced on combustion of 2 Moles of CH₄.