The radio active decay of a substance or any chemical is measured in half-lives because of the period where there are significant changes in the amount of the chemicals. The amount of chemical is almost halved in the next period as is suggested by the given graph.
Using the equation for boiling point elevation Δt
Δt = i Kb m
we can find the new boiling point T for the solution:
Δt = T - 100∘C
since we know that pure water boils at 100 °C.
We know that the van't Hoff Factor i is equal to 1 because sugar does not dissociate in water.
Also, the value of Ebullioscopic constant Kb for water is listed as 0.512 °C·kg/mol.
The molality m of the solution of 6 moles of sugar dissolved in a kilogram of water can be calculated as
m = 6 moles / 1 kg
= 6 mol/kg
Therefore the new boiling point T would be
T - 100 °C = i Kb m
T = i Kb m + 100 °C.
= (1) (0.512 °C·kg/mol) (6 mol/kg) + 100 °C
= 3.072 °C + 100 °C
= 103.072 °C
Answer:
8 mins and 20 seconds i think
Explanation:
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
= 25/1000 liter
= 0.025 liter
V2 = 18 ml
= 18/1000 liter
= 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
= (1 * 0.018)/0.025
= 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
