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3 years ago

Which of the following is not an example of separation by physical means?

Biology

2 answers:

yaroslaw [1]3 years ago

8 0

Evaporation is not an example of separation by physical means.

Alina [70]3 years ago

3 0

C) Electrolysis 

WHY?

electrolysis is a method of using an electric current to drive an otherwise non-spontaneous chemical reaction. Electrolysis is commercially highly important as a stage in the separation of elements from naturally-occurring sources such as ores using an electrolytic cell.

**Sorry if wrong tried my best X3*

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Which is NOT a source of genetic variation among individuals?

mafiozo [28]

I believe its D I hope it helps

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3 years ago

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Consider the clinical scenario: Semen is very low in volume and the sperm cells have difficulty with motility because there isn'

zlopas [31]

Answer:

Seminal vesicle

Explanation:

Seminal vesicle secretes an alkaline and viscous fluid that constitutes about 60% of the volume of semen. The fluid secreted by seminal vesicle contains fructose which is a monosaccharide sugar, prostaglandins, and clotting proteins. The alkaline nature of the seminal fluid neutralizes the acidic environment of the male urethra and the female reproductive tract. This is required as the acidic conditions inactivate and kill sperm.

The fructose sugar serves a fuel for ATP production by sperm. Prostaglandins are responsible for sperm motility and viability as they stimulate smooth muscle contractions within the female reproductive tract. Therefore, a malfunctioning seminal vesicle would result in low semen volume and reduced motility due to the scarcity of energy.

4 0

3 years ago

Explain how famine, disease, and war are more likely with larger populations.

Iteru [2.4K]

Famine- High population means more mouths to feed
Disease- Diseases usually spread more quickly with people who live closer( as it can just move from one person to the other)
War- People like to fight for land, resources, money, etc. And having more of those things mean they are more able to support families, communities, and more.

(Hope this helps a little)

7 0

3 years ago

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The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago

(Question is in the picture)

kramer

Higher on the outside,

because the potatoes feel heavier, that means they must contain more water, which also means they had to have sucked in some water or had more water in them to begin with.

concentration usually likes to go from high to low in order to balance things out, so the only way water could enter the cells through osmosis would be if the concentration of water were higher on the outside of the cells

5 0

3 years ago