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3 years ago

Can someone help me wit this problem it is 20 points and i need to work on it for school and i Am very confused. Please help

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

So the slope of the first line is 4/3. If this line is perpendicular, then you have to flip it and switch the sign (flip it n switch it (how I remember it)). So the slope of the new line is -3/4.
Then you have to plug in the point you're given and the new slope. Use y=mx+b format.
-1=-3/4*-4+b
Then solve for b.
-3/4*-4 is 3.
-1=3+b
Subtract 3 from each side.
-4=b.
So now you have the y-intercept and slope. All you have to do is plug it in.
y=-3/4x + -4 or y=-3/4 - 4
There's your answer!

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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

-9+m=13 for equations

Nataly_w [17]

Answer:

m=22

Step-by-step explanation:

i am very very shmart

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2 years ago

Absolute value equations <br> 10 6v + 3 = 30

konstantin123 [22]

Your answers would be 30

7 0

2 years ago

A box's volume is equal to 600 cubic

olga2289 [7]

Answer:

Step-by-step explanation:

Length = x

width = x - 7

height = x - 10

volume = 600 in^3

Volume = L * w * h

600 = x * (x - 7)*(x - 10)

600 = x * (x^2 - 17x + 70)

600 = x^3 - 17x^2 + 70x

x^3 - 17x^2 + 70x - 600 = 0

There is a genius somewhere that could solve this using algebra. The rest of us have 2 choices. We can graph it (see below) or we could use a program that solves it for us. I'll do both for you.

a = 1

b = - 17

c = 70

d = - 600

There is only 1 real solution: x = 15

L = 15

w = 8

h = 5

That has to be one of the ugliest graphs made. It does into the hundreds of thousands and it still looks like a straight line. Trust me. It's not.

3 0

2 years ago

Beth had 1 yard of ribbon. she used 1/5 yard for a project. She wants to divide the rest of the ribbon into pieces 1/10 yard lon

likoan [24]

1 - (1/5) = 4/5 yards of ribbon.
(4/5) / (1/10) = 8 Pieces of 1/10 Yard Long Ribbons

Hope that Helped you.

4 0

2 years ago