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const2013 [10]
3 years ago
12

Please answer the following

Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

cot∅ = (-2√30)/7.

Step-by-step explanation:

Given the value of csc∅ = -13/7 and ∅ is in quad III.

We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).

It means y = -7, r = 13.

We know x² + y² = r².

x² = r² - y²

x² = (13)² - (-7)² = 169 - 49 = 120.

x = √120 = 2√30.

we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.

Hence, cot∅ = (-2√30)/7.

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The hundreds digit and the ones digit of a three digit number are the same. The sum of its tree digits are 16. If the tens digit
tensa zangetsu [6.8K]
<h2>727</h2>

Step-by-step explanation:

       Let us denote the three digit number by abc, where a is the hundreds digit, b is the tens digit and c is the ones digit.

       Hundreds digit = a = Ones digit = c

       Sum of digits = a+b+c=16

       So, 2c+b=16

       On exchanging tens and ones digit, value increases by 45. So acb is 45 greater than abc.

       acb-abc=45

       100a+10c+b-100a-10b-c=45\\9c-9b=45\\c-b=5

       2c+b=16,c-b=5\\3c=21\\c=7=a\\b=2

∴ Required number is 727

7 0
3 years ago
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Answer:

b. Kilograms

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Help me please !!!!!!
stira [4]

Yes, the relationship is proportional. 3 * 3.2 = 9.6. And 5 * 3.2 = 16.

3 0
2 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
2 years ago
What is the solution to this system of equations?
Lady bird [3.3K]

3x+y=−11

3x+y+−3x=−11+−3x(Add -3x to both sides)

y=−3x−11

2x+2y=−10

2x+2(−3x−11)=−10

−4x−22=−10(Simplify both sides of the equation)

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−4x=12

−4x

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y=−2(Simplify both sides of the equation)

Answer:

x=−3 and y=−2

D.(-3,-2)

8 0
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