Answer:
ω=314.15 rad/s.
0.02 s.
Explanation:
Given that
Motor speed ,N= 3000 revolutions per minute
N= 3000 RPM
The speed of the motor in rad/s given as
Now by putting the values in the above equation
ω=314.15 rad/s
Therefore the speed in rad/s will be 314.15 rad/s.
The speed in rev/sec given as
ω= 50 rev/s
It take 1 sec to cover 50 revolutions
That is why to cover 1 revolution it take
Answer:
Explanation:
The pump is modelled after applying Principle of Energy Conservation, whose form is:
The head associated with the pump is cleared:
Inlet and outlet velocities are found:
Now, the head associated with the pump is finally computed:
The power that pump adds to the fluid is:
Answer:
It’s cool I’d say 8/10 I guess
Explanation:
Answer:
Time of submersion in years = 7.71 years
Explanation:
Area of plate (A)= 16in²
Mass corroded away = Weight Loss (W) = 3.2 kg = 3.2 x 106
Corrosion Penetration Rate (CPR) = 200mpy
Density of steel (D) = 7.9g/cm³
Constant = 534
The expression for the corrosion penetration rate is
Corrosion Penetration Rate = Constant x Total Weight Loss/Time taken for Weight Loss x Exposed Surface Area x Density of the Metal
Re- arrange the equation for time taken
T = k x W/ A x CPR x D
T = (534 x 3.2 x 106)/(16 x 7.9 x 200)
T = 67594.93 hours
Convert hours into years by
T = 67594.93 x (1year/365 days x 24 hours x 1 day)
T = 7.71 years
Answer
1056
Explanation:
for example
A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate
Quantity of soil to be excavated from pit in m3
