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dlinn [17]
1 year ago
9

1.Which thematic group uses technology to direct the behavior of dynamical systems, ensuring that they behave in a predictable m

anner?
2.Which thematic group creates circuits with miniature, packaged components that directs and control electricity?

a.Communication Systems
b.Control Systems
c.Computer Systems
d.Energy Systems
e.Electronic Systems
Engineering
1 answer:
dsp731 year ago
8 0

The thematic group governing the behavior of dynamic system is control system, and the one packaging the miniature components to conduct electricity is electronic system. Thus, option E is correct.

<h3>What are thematic groups?</h3>

The thematic groups comprises of group of people that work over the same idea or the concept. The thematic groups working on different projects and ideas comprised to work with different systems.

The control of dynamic system in order to produce the desirable outcome has been the role of the control system.

The packaging of the electronic miniatures in system that performs the role of direction of electricity is the role of electronic system thematic group. Thus, option E is correct.

Learn more about thematic group, here:

brainly.com/question/32731

#SPJ1

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zysi [14]

<u>Explanation:</u>

5 Horsepower for 30 mins,

(5)(745.7) = 3.7285 KW power delivered

General Efficiency of IC engine = 20%

Power required = \frac{3 \cdot 7285}{0 \cdot 2}=18 \cdot 6425 kw

Energy required per week,

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Lawn area = (30) (20) = 600m^{2}

let sunlight hours be 8 hours

Hence, solar power input on lawn,

=5.62×3600 = 20232 kJ/m^{2}/day

energy input in lawn = (600) (20232) (7)

                                  = 84974.4 mJ/week

Chemical efficiency by photosynthesis = 4%

Chemical content in grass = (84974.4) (0.04)

                                            = 3398.97 mJ

Mass of the clippers  \(=(30)(20)(1 \cdot 096)^{2}(667)\)

                                  \(=478632 \cdot 33\) pounds

Removing water content,

dried grass clippings \(=95726.46\) pound

                                    = 11533.25 gallons

Trash cans repaired  

                                     =\frac{11533}{50} =230.66\\=231 cans

By burning the gas, total energy input = 3398.97 MJ × 0.2

                                                                = 679.794 MJ

Efficiency of steeling engine  =  20%

Energy output by engine = 679.794 ×0.2

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Who plays blox burg???
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Explanation:

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At an axial load of 22 kN, a 15-mm-thick × 40-mm-wide polyimide polymer bar elongates 4.1 mm while the bar width contracts 0.15
Alenkasestr [34]

Answer:

The Poisson's Ratio of the bar is 0.247

Explanation:

The Poisson's ratio is got by using the formula

Lateral strain / longitudinal strain

Lateral strain = elongation / original width (since we are given the change in width as a result of compession)

Lateral strain = 0.15mm / 40 mm =0.00375

Please note that strain is a dimensionless quantity, hence it has no unit.

The Longitudinal strain is the ratio of the elongation to the original length in the longitudinal direction.

Longitudinal strain = 4.1 mm / 270 mm = 0.015185

Hence, the Poisson's ratio of the bar is 0.00375/0.015185 = 0.247

The Poisson's Ratio of the bar is 0.247

Please note also that this quantity also does not have a dimension

3 0
3 years ago
Suppose there are n chairs in a row. We want to compute the number of ways to put 2 students into seats so that they are not nex
icang [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) f_{(n)} = f_{(n-1)} + n-2

b) g_{(n)} = g_(n+1) + (n-2)

Explanation:

The explanation is shown on the second and third uploaded image

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2 years ago
The electron concentration in silicon at T = 300 K is given by
puteri [66]

Answer:

E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m

Explanation:

From the question we are told that:

Temperature of silicon T=300k

Electron concentration n(x)=10^{16}\exp (\frac{-x}{18})

                                        \frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})

Electron diffusion coefficient is Dn = 25cm^2/s \approx 2.5*10^{-3}

Electron mobility is \mu n = 960 cm^2/V-s \approx0.096m/V

Electron current density Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2

Generally the equation for the semiconductor is mathematically given by

Jn=qb_n\frac{dn}{dx}+nq \mu E

Therefore

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E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m

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2 years ago
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