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kap26 [50]
3 years ago
14

What is the term RF exiciter?

Engineering
1 answer:
Sati [7]3 years ago
7 0
The exciter provides fully coherent receiver local oscillator signals at radar frequency band as well as requisite, auxiliary high frequency clock signals. The exciter function is divided into an internal frequency synthesizer and an upconverter.

Hope this helps :)))
You might be interested in
Liquid water enters an adiabatic piping system at 15°C at a rate of 8kg/s. If the water temperature rises by 0.2°C during flow d
Gennadij [26K]

Answer:

23 W/K

Explanation:

Entropy of water at 15°C is 224.5 J/kg/K.

Entropy of water at 15.2°C is approximately 227.4 J/kg/K (interpolated).

The increase in entropy is therefore:

227.4 J/kg/K − 224.5 J/kg/K = 2.9 J/kg/K.

So the rate of entropy generation is:

2.9 J/kg/K × 8 kg/s = 23.2 W/K

Rounded to two significant figures, the rate is 23 W/K.

3 0
3 years ago
3. (5%) you would like to physically separate different materials in a scrap recycling plant. describe at least one method that
Likurg_2 [28]

One of the methods that are used to separate polymers, aluminium alloys, and steels from one another is the Gravitation Separation method.

One straightforward technique is to run the mixture through a magnet, which will keep the steel particles on the magnet and separate them from the polymer.

What is the Gravitation Separation method?

When it is practicable to separate two components using gravity, i.e., when the combination's constituent parts have different specific weights, gravity separation is a technique used in industry. The components can be in suspension or in a dry granular mixture.

Polymers, Steel and Aluminium alloys can be readily split apart. The technique depends on how the two components are combined. The approach used is gravitational density. Due to the significant difference in relative specific mass values between steel and polymers (which range from 1.0 to 1.5), it is possible to separate them using flotation in a liquid that is safe and has the right density.

Therefore, the Gravitation Separation method is used to separate polymers, aluminium alloys and steels.

To learn more about the Polymer from the given link

brainly.com/question/2494725

#SPJ4

8 0
2 years ago
What steps would you take to design an improved toothpaste container?
algol [13]

Answer:

A. Identify the need, recognize limitations of current toothpaste containers, and then brainstorm ideas on how to improve the existing

Explanation:

To design an improved toothpaste container, we must identify the needs of the customer, one of the major need is to make the container attractive to the sight. This is the first thing that will prompt a customer to wanting to buy the product (The reflectance/appearance).

Then recognize the limitation of the current design, what needed change. This will help in determining what is needed to be included and what should be removed based on identified customers need.

The last step is to brainstorm ideas on how to improve the existing designs. Get ideas from other colleagues because there is a saying that two heads are better than one. This will help in coming to a reasonable conclusion on the new design after taking careful consideration of people's opinion.

7 0
3 years ago
The typical measurement of hotel demand is the room night (RN). When we say that each room night is perishable , we mean that on
Marta_Voda [28]

Answer:

Yes once a room is not rented for a couple of hours in the night then it is perishable.

8 0
3 years ago
A unidirectional E-Glass fiber-epoxy composite material contains 61% by volume E-Glass fibers stressed under isostrain condition
zalisa [80]

Answer:

The total load carried by the fiber will be "98%".

Explanation:

The given values are:

V_{f}=0.61

V_{m}=1-V_{f}

     =1-0.61

     =0.39

E_{f}=10 \ Mpa

\sigma_{f}=0.35 \ Mpa

E_{m}=0.45 \ Mpa , \sigma_{m}=9\times 10^{-3} \ Mpa

As we know,

⇒  E_{e}=fE_{f}+mE_{m}

On putting the estimated values, we get

⇒       =0.61\times 10+0.39\times 0.95

⇒       =6.27 \ Mpa

Now,

⇒  \sigma_{c}=f\sigma_{f}+m\sigma_{m}

On putting the estimated values, we get

⇒       =0.61\times 0.35+0.39\times 0.009

⇒       =0.217 \ Mpa

Therefore,

The load carried by fiber,

=\frac{f\sigma_{f}}{\sigma_{c}}

=\frac{0.35\times 0.61}{0.217}

=0.98 i.e., 98%

4 0
4 years ago
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