Answer:
Magnitude of velocity when s is 10 m= 4.58m/s
Magnitude of acceleration when s is 10 m = 0.653 m/s²
Explanation:
Radius of circular path = 50m
Speed = 4m/s
increase in acceleration = (0.05s)m/s²
speed and acceleration when s is 10 m = ?
Magnitude of Velocity:
From third equation of motion
![v_{f}^{2}-v_{i}^{2}=2aS\\\\v_{f}=\sqrt{2aS+v_{i}^{2}} \\\\v_{f}=\sqrt{2(0.05)(10)+(4)^{2}} \\\\v_{f}=4.58\,m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D-v_%7Bi%7D%5E%7B2%7D%3D2aS%5C%5C%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2aS%2Bv_%7Bi%7D%5E%7B2%7D%7D%20%5C%5C%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%280.05%29%2810%29%2B%284%29%5E%7B2%7D%7D%20%5C%5C%5C%5Cv_%7Bf%7D%3D4.58%5C%2Cm%2Fs)
Magnitude of Acceleration:
![a=\sqrt{a_{t}^{2}+a_{n}^{2}}--(1)](https://tex.z-dn.net/?f=a%3D%5Csqrt%7Ba_%7Bt%7D%5E%7B2%7D%2Ba_%7Bn%7D%5E%7B2%7D%7D--%281%29)
The tangential component of acceleration is
![a_{t}=(0.05)(10)\\a_{t}=0.5\,m/s^{2}](https://tex.z-dn.net/?f=a_%7Bt%7D%3D%280.05%29%2810%29%5C%5Ca_%7Bt%7D%3D0.5%5C%2Cm%2Fs%5E%7B2%7D)
The normal component of acceleration is
![a_{n}=\frac{v^{2}}{R}\\\\a_{n}=\frac{16}{50}\\\\a_{n}=0.42\,m/s^{2}](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bv%5E%7B2%7D%7D%7BR%7D%5C%5C%5C%5Ca_%7Bn%7D%3D%5Cfrac%7B16%7D%7B50%7D%5C%5C%5C%5Ca_%7Bn%7D%3D0.42%5C%2Cm%2Fs%5E%7B2%7D)
Substituting tangential and normal component in (1)
![a=\sqrt{(0.5)^{2} +(0.42)^{2} }](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B%280.5%29%5E%7B2%7D%20%2B%280.42%29%5E%7B2%7D%20%7D)
a=0.653 m/s²
Answer: 4I
Explanation:
If we had simply put in parallel with the wire one equal to it, the total current flowing through both resistors would double, due to the equivalent resistance of two resistors of equal value, in parallel, is just the half of one of them, so applying Ohm's Law, I will be double than I₀.
But in this case, everything happens as if we put in parallel two resistors of half the value (as the resistance is directly proportional to the length while Ohm's Law be valid), so the equivalent resistance becomes 1/4 of the original wire.
Applying Ohm's Law, we have I = (V / R/4) ⇒ I = 4 I₀
Answer:
Explanation:
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