Answer:
See below in the explanation section the Matlab script to solve the problem.
Explanation:
prompt='enter the first weight w1: ';
w1=input(prompt);
wd1=double(w1);
prompt='enter the second weight w2: ';
w2=input(prompt);
wd2=double(w2);
prompt='enter the third weight w3: ';
w3=input(prompt);
wd3=double(w3);
prompt='enter the fourth weight w4: ';
w4=input(prompt);
wd4=double(w4);
prompt='enter the first weight w5: ';
w5=input(prompt);
wd5=double(w5);
x=[wd1 wd2 wd3 wd4 wd5]
format short
Answer:
See explaination
Explanation:
Kindly check attachment for the step by step solution of the given problem.
Answer:
yes, it is
Explanation:
The sequence: (+4)
23,27,31,35,39,43,47,51,55,59,63,67,71,75,79,83
Hope this helps! :)
Answer:
The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C
Explanation:
The properties of water at 100°C and 1 atm are:
pL = 957.9 kg/m³
pV = 0.596 kg/m³
ΔHL = 2257 kJ/kg
CpL = 4.217 kJ/kg K
uL = 279x10⁻⁶Ns/m²
KL = 0.68 W/m K
σ = 58.9x10³N/m
When the water boils on the surface its heat flux is:

For copper-water, the properties are:
Cfg = 0.0128
The heat flux is:
qn = 0.9 * 18703.42 = 16833.078 W/m²

The tube surface temperature immediately after installation is:
Tinst = 100 + 20.4 = 120.4°C
For rough surfaces, Cfg = 0.0068. Using the same equation:
ΔT = 10.8°C
The tube surface temperature after prolonged service is:
Tprolo = 100 + 10.8 = 110.8°C