While trying out for the position of pitcher on your high school baseball team, you throw a fastball at 87.6 mi/h toward home pl
ate, which is 18.4 m away. how far does the ball drop due to effects of gravity by the time it reaches home plate? (ignore any effects due to air resistance and assume you throw the ball horizontally.)?
1 answer:
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- Let, the maximum height covered by projectile be
- Projectile is thrown with a velocity = v
- Angle of projection = θ
- Velocity of projectile at a height half of the maximum height covered be
______________________________
Then –
- Now, the vertical component of velocity of projectile at the height half of
will be –
Therefore, the vertical component of velocity of projectile at this height will be–
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Answer:
The length of the boomerang is 0.364 m
Explanation:
The moment of inertia is:
Where
md = 0.05 kg
mh = 0.12 kg
r = d/2 = 0.273/2 = 0.1365 m
The length of the boomerang is: