Answer:
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Explanation:
During the motion of the rock while it is in downward motion we can say

since it is performing circular motion so we will have its acceleration towards its center



So at the lowest point of the path we can say

so correct answer is
a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.
Answer:
0.665
Explanation:
I did the work. Just plug everything in from the formula. Look at the lesson manual.
Your answer is ''Uniform''.
Hope this helps :)
Answer:
The answer is already given... it's 31.25 cm
D, it is considered unethical today