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lora16 [44]
3 years ago
12

Write a balanced molecular equation for the reaction of sodiummetal with water.

Chemistry
1 answer:
9966 [12]3 years ago
5 0

Answer:

Na + H₂O → NaOH + 1/2 H₂

Explanation:

When sodium reacts with water, it forms sodium hydroxide and molecular hydrogen. The unbalanced equation is:

Na + H₂O → NaOH + H₂

We have to balance this equation so it obeys the law of conservation of mass. We have 1 atom of Na on each side and 1 atom of O on each side, so these elements are balanced. However, we have 2 atoms of H on the left side and 3 atoms of H on the right side. The easiest way to balance the H without modifying the other elements is by making 1/2 the stoichiometric coefficient of H₂.

Na + H₂O → NaOH + 1/2 H₂

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Answer:

Copper is a metal made up of copper atoms closely packed together. As a result, the electrons can move freely through the metal. For this reason, they are known as free electrons. They are also known as conduction electrons because they help copper be a good conductor of heat and electricity.

Explanation:

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PLEASE HELP----
balandron [24]
Actual yield of Fe2(So4)3 = 18.5g

2FePo4 + 3Na2SO4 -> Fe2(SO4)3 + 2Na3PO4

Mole of FePO4 = mass of it / its molar mass =
25 g / (55.8 + 31 + 16*4) = 0.166 mol

every 2 mole of FePO4 will form 1 mole of Fe2(SO4)3

Mole of Fe2(SO4)3 produced = 0.166 / 2 = 0.0829 mol

0.0829 * (55.8*2 + 3*(32.1+ 16*4)) = 33.148 g of Fe2(SO4)3

18.5 / 33.148 * 100 = 55.8%

3 0
3 years ago
Calculate ΔHrxn for the following reaction: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) Use the following reactions and given ΔH′s. 2Fe(s)+3/
sesenic [268]

Answer:

The answer to your question is:  ΔHrxm = -23.9 kJ

Explanation:

Data:

2Fe(s)+3/2O2(g)→Fe2O3(s),  ΔH = -824.2 kJ     (1)

    CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ   (2)

Reaction:

                          Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)  

We invert (1) and change the sign of  ΔH

        Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

We multiply (2) by 3

      3(  CO(g)+1/2O2(g)→CO2(g)         ΔH = -282.7 kJ)   (2)

      3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

We add (1) and (2)

Fe2O3(s)   →  2Fe(s)+3/2O2(g)  ΔH = 824.2 kJ

3CO(g)+3/2O2(g)→3CO2(g)         ΔH = -848.1 kJ

Fe2O3(s) +  3CO(g)+3/2O2(g)  →  2Fe(s)+3/2O2 + 3CO2(g)    

Simplify

    Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)    and ΔHrxm = -23.9 kJ

6 0
2 years ago
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