Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
1 answer:
Answer:
-125.4
Explanation:
Target equation is 4C(s) + 5H2(g) = C4H10
These are the data equations for enthalpy of combustion
C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4 H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse
To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...
Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.
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