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vaieri [72.5K]
3 years ago
13

How do you detect which material is going to be positively charged or negatively charged?

Chemistry
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

If a material gains electrons, its going to be Negatively charged

If a material loses electrons, its gonna be positively charged.

Explanation:

Why?

This is because electrons are negative subatomic particles

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Which of the following correctly describes the law of conservation of energy
egoroff_w [7]
Mass and energy can not be created or destroyed, they may be able to just be converted, and neither one seems without the opposite. For this reason in closed systems, both mass and energy are conserved individually. " I hope this helps "
3 0
3 years ago
Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
iVinArrow [24]

The  number of atoms  of K that are in 235 g  of the compound  is

2.57 x10^24 atoms


 calculation

Step 1:  find the moles of K2S

= moles = mass/molar mass

=  235 g/110 g/mol= 2.136  moles

Step 2: multiply  2.136 moles  by no. of K atoms in K2S

= 2.136  x2 = 4.272 moles


Step 3: use the Avogadro's  law to determine number of K atoms

that is according to Avogadro's law  1 mole = 6.02 x 10^23  atoms

                                                            4.272 moles= ? atoms

by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

4 0
3 years ago
PLS HELP IF YOU WANT A BRAINLIEST BEST ANSWER CHOICE GETS BRAINLIEST Which describes the two cells formed through mitosis?
luda_lava [24]

Answer:C

Explanation:

did it

6 0
3 years ago
In the following reaction, which component acts as an oxidizing agent? 10 I− (aq) + 2 MnO4− (aq) + 16 H+ (aq) → 5 I2 (s) + 2 Mn2
antiseptic1488 [7]

Answer:

The oxidizing agent is the MnO₄⁻

Explanation:

This is the redox reaction:

10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)

Let's determine the oxidation and the reduction.

I⁻ acts with -1 in oxidation state and changes to 0, at I₂.

All elements in ground state has 0 as oxidation state.

As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.

In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine

3 0
3 years ago
temperature change in Metals metal specific heat initial temperature final temperature copper 0.39 100°C 27°C aluminum 0.90 100°
kolbaska11 [484]

Answer:

a

Explanation:

6 0
4 years ago
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