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ivolga24 [154]
1 year ago
14

How many grams are in 4 5 moles of sodium fluoride naf

Chemistry
1 answer:
nekit [7.7K]1 year ago
3 0

There are 618.68 g in 4.5 moles of NaF.

The total number of moles of any substance equals the ratio of its given mass in a chemical reaction to the mass of one mole or molar mass of that substance.

It is known that one mole of NaF or molar mass of NaF is 41.98 g/mol.

Given that number of moles is 4.5 moles.

Therefore, calculate the mass of NaF in grams as follows.

No. of moles = Given mass / Molar mass

mass in grams = No. of moles × Molar mass

                        = 4.5moles × 41.98 g/mol

                        = 188.91 g

Hence, we can conclude that there are 188.91 g in 4.5 moles of NaF.

Learn more about NaF from the link given below.

brainly.com/question/21321048

#SPJ4

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satela [25.4K]

Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

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2.- Calculate the proportions

theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

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As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

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         x = (400 x 112) / 160

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          400 g of Fe₂O₃  --------------  x

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         x = 330 gr

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