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ivolga24 [154]
1 year ago
14

How many grams are in 4 5 moles of sodium fluoride naf

Chemistry
1 answer:
nekit [7.7K]1 year ago
3 0

There are 618.68 g in 4.5 moles of NaF.

The total number of moles of any substance equals the ratio of its given mass in a chemical reaction to the mass of one mole or molar mass of that substance.

It is known that one mole of NaF or molar mass of NaF is 41.98 g/mol.

Given that number of moles is 4.5 moles.

Therefore, calculate the mass of NaF in grams as follows.

No. of moles = Given mass / Molar mass

mass in grams = No. of moles × Molar mass

                        = 4.5moles × 41.98 g/mol

                        = 188.91 g

Hence, we can conclude that there are 188.91 g in 4.5 moles of NaF.

Learn more about NaF from the link given below.

brainly.com/question/21321048

#SPJ4

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Calculate the number of grams in 4.56 x 1026 atoms of sodium phosphate. Be sure to balance the charges of sodium phosphate. Help
zalisa [80]

Answer:

124225.91 g of Na₃PO₄

Explanation:

From the question given above, the following data were obtained:

Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms

Mass of Na₃PO₄ =?

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Na₃PO₄

Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:

1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)

= 69 + 31 + 64

= 164 g

Thus,

6.02×10²³ atoms = 164 g of Na₃PO₄

Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:

6.02×10²³ atoms = 164 g of Na₃PO₄

Therefore,

4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³

4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄

Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms

4 0
2 years ago
Hi! help me please. CALCULATE THE NUMBER OF MOLECULES FOUND IN 8 MOL OF WATER?
kvasek [131]

Answer:

so the number of molecules in 8 moles of water is 4.8176×10^24

Explanation:

number of moles=8moles

avogadro's number=6.022×10²³

number of molecules=?

as we know that

number of moles=\frac{number of molecules}{avogadro's number}

substituting the equation

number of moles × avogdro's number=number of molecules

number of molecules=8moles×6.022×10²³

number of molecules=4.8176×10^24

i hope this will help you :)

4 0
3 years ago
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
lidiya [134]

Answer:

[Cr(NH3)6.]C13

Explanation:

Alfred Werner's coordination theory (1893) recognized two kinds of valency;

Primary valency which are nondirectional and secondary valency which are directional.

Hence, the number of counter ions precipitated from a complex depends on the primary valency of the central metal ion in the complex.

We must note that it is only these counter ions that occur outside the coordination sphere that can be precipitated by AgNO3.

If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

3 0
2 years ago
When heating liquid materials in laboratory glassware, a student should always
Lelechka [254]

Answer:

be careful to not hurt yourself

5 0
3 years ago
Read 2 more answers
Nitrogen has two isotopes. One has an atomic mass of 14.003
Ilia_Sergeevich [38]

Answer:

d= 14.007 amu

Explanation:

Abundance of N¹⁴ = 99.63%

Abundance of N¹⁵ = 0.37%

Atomic mass of N¹⁴ = 14.003 amu

Atomic mass of N¹⁵ = 15.000 amu

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100

Average atomic mass =  1395.12 + 5.55 / 100

Average atomic mass  = 1400.67/ 100

Average atomic mass = 14.007 amu.

6 0
2 years ago
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