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finlep [7]
3 years ago
15

An earth satellite remains in orbit at a distance of 13594 km from the center of the earth. what is its period? the universal gr

avitational constant is 6.67 × 10−11 n · m2 /kg2 and the mass of the earth is 5.98 × 1024 kg.
Physics
1 answer:
ZanzabumX [31]3 years ago
6 0
Given: Mass of earth Me = 5.98 x 10²⁴ Kg
           Radius of satellite - radius of the earth

           r = 13,594 Km - 6,380 Km = 7,214 Km    convert to meter "m"

           r = 7,214,000 m
            G = 6.67 x 10⁻¹¹ N.m²/Kg²
Required: What is the period T = ?
Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r
               but V = 2πr/T
equate T from all equation.
F = ma
GMeMsat/r² = Msat4π²/rT²    
GMe = 4π²r³/T²
T² = 4π²r³/GMe  

T² = 39.48(7,214,000 m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.48 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 37,092,731.83 s²

T = 6,090.38 seconds    or  1.7 Hr

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Explanation:

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8 0
3 years ago
At 7.0°c, the volume of a gas is 49 ml. at the same pressure, its volume is 74 ml at what temperature?
Rashid [163]
So i converted everything first; 
<span>7.0 C ---> 280 K </span>
<span>49 mL---> 0.049 L </span>
<span>74mL---> 0.074 L </span>
<span>THEN I tried setting it up by the combined law formula which is P1V1/T1=P2V2/T2 </span>
8 0
3 years ago
Q1- the speed will increase because the particles will have more energy which causes them to move faster
trasher [3.6K]
<h3># Question </h3>

Q1- the speed will increase because the particles will have more energy which causes them to move faster

Explanation:

<h3>With an increase in temperature, the particles gain kinetic energy and move faster. The actual average speed of the particles depends on their mass as well as the temperature – heavier particles move more slowly than lighter ones at the same temperature. </h3>
6 0
3 years ago
Two coils connected in series have a resistance of 36 ohm and when connected in parallel have a resistance of 8ohm. Find resista
nadezda [96]

Answer:

Explanation:

Remark

Two resistances in series has the form of

Rs= C1 + C2

Two resistances is parallel has the form of

Rp = (C1 *C2)/(C1 + C2)

The plan is to first of all find C1*C2 and use this information and C1 + C2 to find the individual resistances.

Givens

Rs = 36 ohms

Rp = 8 ohms

Solution

Rp = C1 * C2/(C1 + C2)

Rp = 8 ohms

C1 + C2 = 36 ohms

8 =    C1*C2 / 36                          Multiply by 36

8* 36 = C1*C2

C1*C2 = 288

Use Rs to solve for C1

  • C1 + C2 = 36
  • C1 = 36 - C2

(36 - C2) * C2 = 288

36*C2 - C2^2 =288                    Multiply by - 1

-36C2 + C2^2 = -288                 Add 288 to both sides

C2^2 - 36C2 + 288= 0               Factor this equation

(C2 - 12)(C2 - 24)

C2 - 12 = 0

C2 = 12

C2 - 24 = 0

C2 = 24

<em> </em>

C2 = 24 or

C2 = 12

C1 = 36 - C2

C1 = 36 - 24 = 12

C1 = 36 - 12  = 24

Answer

<u><em>C1 = 12 ohms or 24 ohms</em></u>

<u><em>C2 = 24 ohms or 12 ohms</em></u>

7 0
3 years ago
Explain why a city with the same latitude but higher elevation will have a lower temperature
dezoksy [38]
The higher the altitude the less molecules in the air.
5 0
4 years ago
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