Answer:
Explanation:
Ah is a unit of charge .
A battery with 12 V and charge capacity of 40 Ah will have energy content
= volt x charge
volt = 12 V
Charge = 40 Ah
= 40 x 60 x 60 A.s
= 144000 coulomb
energy content = 12 x 144000
= 1728000 J
energy content of heavy duty battery
= 12 x 60 x 60 x 60
= 2592000 J
Ratio = 1728000 / 2592000
= 2 / 3
Current can not be compared as current depends upon the resistance of appliance used . As resistance of appliance is unknown , current can not be compared.
Answer:
a) No. The kinetic energy of the ball decreases.
b) The potential energy of the ball increases.
c) The ball would go half of the original distance.
Explanation:
a) The kinetic energy would be converted to potential energy as the ball goes higher. Since the total mechanical energy is conserved, the kinetic energy would decrease.
b) The potential energy of the ball would increase. Since the total mechanical energy of the ball is conserved, the ball would lose speed, and therefore kinetic energy. In order to compensate the loss of kinetic energy, the ball would gain potential energy as it goes higher.
c) The relation of the energy and mass is as follows:
According to the energy conservation
The maximum height that the ball reaches is proportional to the initial velocity. If the ball would be imparted with the same amount of energy, its final potential energy would be the same. However, in order to have the same potential energy (mgh), its height would be half of the original case.
Answer:
2.9 N
Explanation:
When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:
F = (k * q1 * q2) / r²
Where F = force acting on the balloons
k = Coulombs constant
Therefore:
0.32 = (k * q1 * q2) / 0.5²
=> k * q1 * q2 = 0.32 * 0.5² ------------(1)
When the distance is decreased by 3, that is r = r/3 = 0.5/3
F = (k * q1 * q2) / (0.5/3)² ------------(2)
Putting (1) into (2):
=> F = (0.32 * 0.5²) / (0.5/3)²
F = (0.32 * 0.5² * 3²) / 0.5²
F = 2.9 N
Therefore, the force would be 2.9 N
You have several electrical units listed there:
a). C often used to represent a Capacitance.
b). 'A' often represents 'Ampere', the unit of Current.
c). 'R' often used to represent a Resistance.
d). 'E' often used to represent a Voltage (Electromotive Force).
Not to mention ' A. C ', a whimsical offering,
reminiscent of 'Alternating Current'.
