Answer:
the cart's speed at point B is 15.72 ft/s
Explanation:
Given the data in the question;
The car travels from point A to C in 3.00 s, its average acceleration 
will be;
= [
- 
] / Δt
is 17.4 ft/s, is 13.2 ft/s and Δt is 3.00 s
so we substitute
= [17.4 - 13.2] / 3
= 4.2 / 3
= 1.4 ft/s²
so average acceleration of the cart between the points A and B is 1.4 ft/s²
The instantaneous value of the velocity of the cart at point B will be;
= Δv / Δt
now substitute [ - 
] for Δv and t' for Δt
= [ - ] / t'
= - ( t' )
so we substitute 17.4 ft/s for , 1.20 s for t' and = 1.4 ft/s²
= 17.4 - (1.4 × 1.20)
= 17.4 - 1.68
= 15.72 ft/s
Therefore, the cart's speed at point B is 15.72 ft/s
Answer:
the matric is based on the number 10
Work is force times
distance. <span>
The distance is 1.3 m/s x 7.6 s = 9.88 m </span>
<span>
the force is only sufficient force to overcome friction.
Assuming the table is a level table, the force to overcome friction is µ x
normal force = 0.6 x (12 kg) x 9.8 m/s^2 = 70.56 N </span>
<span>
So the work is 70.56 N x 9.88 m = 697.13 J
<span>The power is simply the work / time = 697.13 J / 7.6 s = 91.7
or 92 Watts </span></span>
The exponential growth/decay formula is given by A = Pe^(rt), where A is the final amount, P is the initial amount, r is the rate of growth/decay and t is time.
We are given A = (1/500)P and t=1, so substituting:
(1/500)P = Pe^(r*1)
Cancelling out P on both sides:
1/500 = e^r
ln(1/500) = ln(e^r)
r = -6.215
Rate of decay is -6.215 per day.
<span>It is false that in order to become a personal trainer, a bachelor's degree is usually needed. The minimal requirements for such a job would be a diploma, or a certificate that you have the necessary skills and knowledge in order to become a personal trainer, but you do not need a faculty degree in order to perform this job. Your skills are far more improtant than the paper from a university.</span>
