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seropon [69]
3 years ago
8

When are tides highest? a. during the moon’s first quarter phase b. when the sun, Earth, and the moon are nearly in a line c. du

ring the moon’s third quarter phase d. when the moon is at a right angle to the sun
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
<span>Ocean tides are highest when the sun, Earth, and the moon
are nearly in a line.  That means at the times of New Moon
and Full Moon.</span>
liubo4ka [24]3 years ago
3 0

Answer:

b. when the sun, Earth, and the moon are nearly in a line

Explanation:

Due to gravitational pull of sun and moon, the level of water in seas and oceans rises above its normal level. This is known as tides. Highest tides occur when the sun, the moon and the Earth align in a straight line i.e. during New moon and Full moon. This is because in this alignment, there is maximum effect of gravity. Tide occurrence during this phase are also referred as spring tides.

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A straight fin is made from copper (k = 388 W/m-K) and is 0.5 cm in diameter and 30 cm long. The temperature at the base of the
erastovalidia [21]

Answer:

The rate of transfer of heat is 0.119 W

Solution:

As per the question:

Diameter of the fin, D = 0.5 cm = 0.005 m

Length of the fin, l =30 cm = 0.3 m

Base temperature, T_{b} = 75^{\circ}C

Air temperature, T_{infty} = 20^{\circ}

k = 388 W/mK

h = 20\ W/m^{2}K

Now,

Perimeter of the fin, p = \pi D = 0.005\pi \ m

Cross-sectional area of the fin, A = \frac{\pi}{4}D^{2}

A = \frac{\pi}{4}(0.5\times 10^{-2})^{2} = 6.25\times 10^{- 6}\pi \ m^{2}

To calculate the heat transfer rate:

Q_{f} = \sqrt{hkpA}tanh(ml)(T_{b} - T_{infty})

where

m = \sqrt{\frac{hp}{kA}} = \sqrt{\frac{20\times 0.005\pi}{388\times 6.25\times 10^{- 6}\pi}} = 41.237

Now,

Q_{f} = \sqrt{20\times 388\times 0.005\pi\times 6.25\times 10^{- 6}\pi}tanh(41.237\times 0.3)(75 - 20) = 0.119\ W

5 0
3 years ago
.Golden Rice is an example of genetically modified organism. <br> true or false
MissTica

Answer:

True

Explanation:

Golden Rice is an example of genetically modified organism.

7 0
3 years ago
Read 2 more answers
PLEASE HELP
blagie [28]
Assuming Adam is on earth g= 9.8 m/s and m= weight/ gravity = 667/9.8 = 68 kg
8 0
3 years ago
The platform height for Olympic divers is 10 m. A 60 kg diver steps off the platform to begin his dive.
azamat

Answer:

a) Ep = 5886[J]; b) v = 14[m/s]; c)   W = 5886[J]; d) F = 1763.4[N]

Explanation:

a)

The potential energy can be found using the following expression, we will take the ground level as the reference point where the potential energy is equal to zero.

E_{p} =m*g*h\\where:\\m = mass = 60[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 10 [m]\\E_{p}=60*9.81*10\\E_{p}=5886[J]

b)

Since energy is conserved, that is, potential energy is transformed into kinetic energy, the moment the harpsichord touches water, all potential energy is transformed into kinetic energy.

E_{p} = E_{k} \\5886 =0.5*m*v^{2} \\v = \sqrt{\frac{5886}{0.5*60} }\\v = 14[m/s]

c)

The work is equal to

W = 5886 [J]

d)

We need to use the following equation and find the deceleration of the diver at the moment when he stops his velocity is zero.

v_{f} ^{2}= v_{o} ^{2}-2*a*d\\where:\\d = 2.5[m]\\v_{f}=0\\v_{o} =14[m/s]\\Therefore\\a = \frac{14^{2} }{2*2.5} \\a = 39.2[m/s^2]

By performing a sum of forces equal to the product of mass by acceleration (newton's second law), we can find the force that acts to reduce the speed of the diver to zero.

m*g - F = m*a

F = m*a - m*g

F = (60*39.2) - (60*9.81)

F = 1763.4 [N]

3 0
3 years ago
Two objects have charges 2.0 C and 1.0 C. If the objects are placed 2 meters apart, what is the magnitude of the force that the
kondor19780726 [428]

Answer:

4.5\cdot 10^9 N

Explanation:

The electric force between two charged objects is given by:

F=k\frac{q_1 q_2}{r^2}

where:

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is their separation

In this problem:

q1 = 2.0 C

q2 = 1.0 C

r = 2 m

So, the electric force is

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(2.0 C)(1.0 C)}{(2 m)^2}=4.5\cdot 10^9 N

4 0
4 years ago
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