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seropon [69]
3 years ago
8

When are tides highest? a. during the moon’s first quarter phase b. when the sun, Earth, and the moon are nearly in a line c. du

ring the moon’s third quarter phase d. when the moon is at a right angle to the sun
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
<span>Ocean tides are highest when the sun, Earth, and the moon
are nearly in a line.  That means at the times of New Moon
and Full Moon.</span>
liubo4ka [24]3 years ago
3 0

Answer:

b. when the sun, Earth, and the moon are nearly in a line

Explanation:

Due to gravitational pull of sun and moon, the level of water in seas and oceans rises above its normal level. This is known as tides. Highest tides occur when the sun, the moon and the Earth align in a straight line i.e. during New moon and Full moon. This is because in this alignment, there is maximum effect of gravity. Tide occurrence during this phase are also referred as spring tides.

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It was a dark and stormy night.Buffy hameard thunder exactly 6 secounds after she saw lightning , the temperature of air is 15°C
SashulF [63]

Answer:

υ = 345.82 m/s

Explanation:

The formula used to find the speed of sound in air, at different temperatures is given as follows:

v = v_{0}\sqrt{\frac{T}{273} }

where,

υ = speed of sound at given temperature  = ?

υ₀ = speed of sound at 0°C = 331 m/s

T = temperature in K = 15°C + 273 = 298 k

Therefore, using these values in the equation, we get:

v = (331 m/s)\sqrt{\frac{298 k}{273 k}}\\

<u>υ = 345.82 m/s</u>

5 0
3 years ago
The sun is made up mostly of
mezya [45]
The sun is made mostly up of Hydrogen.
3 0
4 years ago
Read 2 more answers
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
What's the meaning of quantum entanglement?​
spayn [35]

Answer:

the phenomenon whereby a pair of particles are generated in such a way that the individual quantum states of each are indefinite until measured, and the act of measuring one determines the result of measuring the other, even when at a distance from each other.

3 0
2 years ago
Read 2 more answers
Look at the diagram provided. What would be the mechanical energy at Point #4?
goblinko [34]

Answer:

18000 J

Explanation:

From the question given above, the following data were obtained:

At point 4:

Mass of cart = 600 Kg

Velocity of cart (v) = 7.745 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 600 × 7.745²

KE = 300 × 7.745²

KE ≈ 18000 J

Therefore, the mechanical energy of the cart at point 4 is 18000 J

6 0
3 years ago
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