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3 years ago

A(-3, 0) B(2, 4) C(6, -1) D(1, -5) What is the perimeter and area of quadrilateral ABCD?

Mathematics

1 answer:

Sloan [31]3 years ago

7 0

Answer:

Step-by-step explanation:

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1. ) Find the mean for each data set. ROUND FINAL ANSWERS TO THE TENTHS PLACE.

arlik [135]

Answer:

710

Step-by-step explanation:

81+74+72+66+67+72+66+66+72+65+71= 701

701 rounded to the nearest tenth is 710

7 0

3 years ago

Please tell me the answer as quick as possible! Stuck here badly :(

olga2289 [7]

63degrees

Step-by-step explanation:

there are multiple ways to do this

for one, angle a = angle e (corresponding angles)

angle f + angle e = 180 degrees (angles on a straight line)

angle f = 180 degrees - angle e where angle e = angle a = 117degrees

so angle f = 63 degrees.

4 0

3 years ago

Work out the volume of the shape

pashok25 [27]

Answer:

$\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}$

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

$V_c=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

$V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3$

The formula of a volume of a sphere:

$V_s=\dfrac{4}{3}\pi R^3$

R - radius

Therefore the formula of a volume of a half-sphere:

$V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3$

We have R = 7cm. Substitute:

$V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3$

The volume of the given shape:

$V=V_c+V_{hs}$

Substitute:

$V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3$

7 0

3 years ago

Can someone correct me I’m kinda bad at this plz I beg u

-Dominant- [34]

Answer:

First one-3

Second one-0

Last one-12

Step-by-step explanation:

7 0

3 years ago

2x + 5y = 10 5y x + 2. + = 4

elena-s [515]

Could you attach photo of a problem. It appears 2+..... =4 is missing

4 0

3 years ago