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fredd [130]
3 years ago
10

In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their b

acks against the wall. the cylinder begins to rotate about a vertical axis. then the floor on which the passengers are standing suddenly drops away! if all goes well, the passengers will "stick" to the wall and not slide. clothing has a static coefficient of friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70. what is the minimum rotational frequency, in rpm, for which the ride is safe?
Physics
1 answer:
Vesna [10]3 years ago
7 0
<span>The friction force ( µ . N ) must be enough to counter the gravity force ( m . g ) The Normal force from the rotating wall is the centripetal force = mv^2 / r so with the lowest coefficient of friction ( 0.4 ) 0.4 . v^2 / 2.5 = g v^2 = 2.5 . 9.8 / 0.4 v = 7.83 m/s T = 5π / 7.83 = 2.007 s f = 0.5 Hz = 30 rpm</span>
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serious [3.7K]

Answer:

f=0.1

Explanation:

Use the equation:

f=\frac{1}{T} (where T is the period)

f=\frac{1}{9} (9 comes from the period of a full wavelength)

f=0.1

6 0
2 years ago
An asteroid, whose mass is 3.6 × 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is
frosja888 [35]

Answer:

a) 2.02 years

b) 8.1 x 10⁻⁸.

Explanation:

Time period of a rotating body T² is proportional to radius of orbit R³ So

T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)

1² / T₂² =( 1/1.6)³

T₂ = 2.02 years.

Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)

= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R

Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =

(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)

=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .

7 0
3 years ago
Show that a light ray that strikes two mutually perpendicular reflecting surfaces is reflected back exactly parallel to the dire
DedPeter [7]

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3 0
3 years ago
When solid surfaces slide over each other, the kind of friction that occurs is called sliding friction.
LekaFEV [45]

Answer:

True

Explanation:

A sled sliding across snow or ice. Skis sliding against snow. A person sliding down a slide is an example of sliding friction. A coaster sliding against a table. Two cards in a deck sliding against each other. All of these are examples of sliding friction.

Hope this helps! :)

6 0
4 years ago
Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to h
slamgirl [31]

Answer:

Explanation:

Resistivity and resistance are proportional and depends of the length and the cross-sectional area of the wire:

R=\frac{L}{A}\rho

furthermore, the density is the mass divided by the volume, and the volume can be written as the area multiplyed by the length:

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Now you have tw equations and two variables, so you can solve for each of them.

first, solve for A in both equations and replace them:

\frac{L}{R}\rho=\frac{m}{\rho_mL}

L^2=\frac{mR}{\rho_m \rho} \\L=

now replace this into any of the previous equiations:

R=\frac{\sqrt{\frac{mR}{\rho_m \rho} } \rho}{A} \\A=\sqrt{\frac{mR\rho^2}{\rho_m \rho R^2} }\\A=\sqrt{\frac{m\rho}{\rho_m R} }

If you assume the wire has circular cross-sectional area, then the area is:

A=\pi(\frac{d}{2} )^2

solving for d:

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replacing A and simplifying:

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5 0
3 years ago
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