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kvv77 [185]
2 years ago
7

Suppose a car's standard tires are replaced with tires 1.30 times larger in diameter.(i) Will the car's speedometer reading be (

a) 1.69 times too high,(b) 1.30 times too high,(c) accurate,(d) 1.30 times too low,(e) 1.69 times too low, or (f) inaccurate by an unpredictable factor?
Physics
1 answer:
Nezavi [6.7K]2 years ago
5 0

The answer is 1.30 times too low.

<h3>What is a speedometer reading?</h3>
  • According to the law, speedometers can never understate a vehicle's speed while never exceeding 110% of the real speed + 6.25 mph. Therefore, if you're traveling at 40 mph, your speedometer may display up to 50.25 mph, but it will never show a speed below 40 mph.
  • While the speedometer displays how fast your car is moving, the odometer displays how far it has traveled. According to Tetzlaff, the speedometer's accuracy in most cars, including Volkswagens, is typically within a few percentage points of actual speed.
  • A car's speedometer is a tool that displays the vehicle's speed. An odometer is yet another accessory connected to a speedometer. The car's odometer displays the distance driven. The speedometer, as we all know, displays the pace of every single moment.
  • Federal law prohibits speedometers from having an inaccuracy of more than 5% (usually stated as plus/minus 2.5% relative to the real speed), according to Dan Edmunds, an automotive engineer and director of vehicle testing at Edmunds.com.

The answer is 1.30 times too low.

To learn more about speedometers, refer to:

brainly.com/question/3397467

#SPJ4

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A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km. What is his displacement from the
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Explanation:

Given that,

A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.

We need to find his displacement from the starting position.

We know that,

Displacement = shortest path covered

D=\sqrt{9^2+12^2} \\\\D=15\ km

For direction,

\theta=\tan^{-1}(\dfrac{d_y}{d_x})\\\\\theta=\tan^{-1}(\dfrac{12}{9})\\\\= $$53.13^{\circ}

Hence, this is the required solution.

5 0
3 years ago
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant
PIT_PIT [208]

Answer:

9.96\cdot 10^{-10}J

Explanation:

The capacitance of the parallel-plate capacitor is given by

C=\epsilon_0 k \frac{A}{d}

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2 is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F

Now we can calculate the energy of the capacitor, given by:

U=\frac{1}{2}CV^2

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J

4 0
3 years ago
All points to the blank of zero on a horizontal number line are negative.
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All points to the left of zero on a horizontal number line are negative. A  number line<span> is a picture of a graduated straight </span>line<span> that serves as abstraction for real </span>numbers. <span>This </span>number line<span> can be extended to the left to </span>represent numbers<span> which are smaller than </span>0<span>. Such </span>numbers<span> are called negative </span>numbers<span>.</span>
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Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart
Anna71 [15]
If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.
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3 years ago
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A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire
Marrrta [24]

Answer:

A) 2.89 × 105 N/C, radially inward

Explanation:

The magnitude of the electric field generated by a charged sphere is given by the following formula:

E=k\frac{Q}{r^2}  ( 1 )

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Q: charge of the sphere = -6.50*10^-6 C

r: distance from the center of the sphere to the point in which E is calculated

r = 0.150m + 0.300m = 0.450 m

You replace the values of Q and r in the equation (1):

E=(8.98*10^9Nm^2/C^2)\frac{6.50*10^{-6}C}{(0.450m)^2}=288246.91\frac{N}{C}\\\\E\approx2.89*10^5\frac{N}{C}

The electric field points radially inward because the charge is negative.

hence, the answer is:

A) 2.89 × 105 N/C, radially inward

7 0
3 years ago
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