Answer: a. 17.7 KJ/Mol
b. T=210K
Explanation:
Arsine, ash3 is a highly toxic compound used in the electronics industry for the production of semiconductors. its vapor pressure is 35 torr at – 111.95°c and 253 torr at – 83.6°c. using these data calculate.
the question isnt completely originally, but we could look at the likely derivation from the questions
(a) the standard enthalpy of vaporization
using the clausius clapeyron equation
In (PT1vap / PT2vap) = delta H (vap) / R ( (1/T1) - (1/T2) )
In (35Torr/253Torr) = delta H (vap) / 8.3145 ( (1/189.55) - (1/161.2) )
Therefore, Delta H (vap) = 17.7 KJ/Mol
b. Also the boiling point
What is the normal boiling point of arsine?
At the boiling point Pvap = atmospheric pressure = 1 atm=760 torr
substitution into the equation as stated in question 1
ln(760/253)=17700/8.314(1/189.55-1/T)
T=210K
Answer:
D. n=6 to n=2
Explanation:
Given;
energy of emitted photon, E = 3.02 electron volts
The energy levels of a Hydrogen atom is given as; E = -E₀ /n²
where;
E₀ is the energy level of an electron in ground state = -13.6 eV
n is the energy level
From the equation above make n, the subject of the formula;
n² = -E₀ / E
n² = 13.6 eV / 3.02 eV
n² = 4.5
n = √4.5
n = 2
When electron moves from higher energy level to a lower energy level it emits photons;

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2
Therefore, The electron energy-level transition is from n = 6 to n = 2
Answer:
4.54
Explanation:
X+10X=50
11X=50
X=4.54#
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High density because it is obvious it will be hard to rip and tear.
First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.
To solve this, you will want to create a proportion.
Flagpole height/flagpole shadow=building height/building shadow
Therefore, it should look like this:
50/30= 300/x
Solve for x:
50x=9,000
X= 180 feet
YOUR ANSWER IS C.