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4 years ago

What is the effect of temperature on the solubility of a solid in a liquid

2 answers:

7 0

For many solids dissolved in liquid water, the solubility increases with temperature.

wel4 years ago

4 0

Answer:

If the temperature of the liquid is increased, then more sugar will dissolve, because warm solutions hold more solute than cold solutions.

Explanation:

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The compound CH3CH2-SH is in the organic family known as

Georgia [21]

The compound ch3ch2-sh is in the organic family know as c. thiols

7 0

3 years ago

Answer #4 and #5 make sure you have proof and will give brainliest

sweet-ann [11.9K]

Answer:

B,C

Explanation:

7 0

3 years ago

Read 2 more answers

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0

grandymaker [24]

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of $CO_2$

$\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles$

b) moles of $H_2O$

$\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles$

$6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2$

According to stoichiometry :

6 moles of $CO_2$ require = 6 moles of $H_2O$

Thus 2.0 moles of $CO_2$ require= $\frac{6}{6}\times 2.0=2.0moles$ of $H_2O$

Thus $CO_2$ is the limiting reagent as it limits the formation of product.

As 6 moles of $CO_2$ give = 1 moles of glucose

Thus 2.0 moles of $CO_2$ give = $\frac{1}{6}\times 2.0=0.33moles$ of glucose

Mass of glucose = $moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g$

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water

8 0

3 years ago

Which one of the following that would diffuse more slowly n2o5 or so3

RUDIKE [14]

N2o5 would diffuse more slowly

7 0

3 years ago

Which of the following substances would you predict to have the highest DHvap? Group of answer choices CH3CH2CH2CH3 CH3CH2OH HF

Katyanochek1 [597]

Answer:

a) $CH_3CH_2CH_2CH_3$

Explanation:

In this question we have the following answer choices:

a) $CH_3CH_2CH_2CH_3$

b) $CH_3CH_2OH$

c) $HF$

d) $CH_3Cl$

e) $HOCH_2CH_2OH$

We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:

a) $CH_3CH_2CH_2CH_3$ (Van der waals interactions)

b) $CH_3CH_2OH$ (Hydrogen bonding)

c) $HF$ (Hydrogen bonding)

d) $CH_3Cl$ (Dipole-dipole interaction)

e) $HOCH_2CH_2OH$ (Hydrogen bonding)

For molecules b, c and e we have hydrogen bond to a heteroatom (O, N, S, or P). In this case oxygen, therefore we will have hydrogen bonding interactions (a very strong interaction). So, we can discard these ones.

In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a dipole (due to the electronegativity difference). If we have a dipole, we will have a dipole-dipole interaction (a strong interaction, less than hydrogen bonding but still is a strong interaction).

In molecule a, we have only Van der Waals interactions because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a non-polar molecule. These interactions are the weakest interactions of all the molecules given. So, if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure. 

7 0

3 years ago