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olga2289 [7]
3 years ago
10

What is the effect of temperature on the solubility of a solid in a liquid

Chemistry
2 answers:
krok68 [10]3 years ago
7 0
For many solids<span> dissolved in </span>liquid<span> water, the </span>solubility <span>increases with </span>temperature<span>.</span>
wel3 years ago
4 0

Answer:

If the temperature of the liquid is increased, then more sugar will dissolve, because warm solutions hold more solute than cold solutions.

Explanation:

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In the equation:
Ksenya-84 [330]

Answer:

B) 16 g

Explanation:

  • 2H₂ + O₂ → 2H₂O

First we <u>convert 4 moles of O₂ into moles of H₂</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 4 mol O₂ * \frac{2molH_2}{1molO_2} = 8 mol H₂

Finally we <u>convert 8 moles of H₂ into grams</u>, using <em>its molar mass</em>:

  • 8 mol H₂ * 2 g/mol = 16 g

Thus, the correct answer is option B).

6 0
3 years ago
When 61.6 g of alanine (C3H7NO2) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2
MrRissso [65]

Answer:

Explanation:

From the given information:

TO start with the molarity of the solution:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ C_3H_7 NO_3}{89.1 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

= 0.601 mol/kg

= 0.601 m

At the freezing point, the depression of the solution is \Delta \ T_f = T_{solvent}- T_{solution}

\Delta \ T_f = 2.9 ^0 \ C

Using the depression in freezing point, the molar depression constant of the solvent K_f = \dfrac{\Delta T_f}{m}

K_f = \dfrac{2.9 ^0 \ C}{0.601 \ m}

K_f = 4.82 ^0 C / m}

The freezing point of the solution \Delta T_f = T_{solvent} - T_{solution}

\Delta T_f = 7.3^ 0 \ C

The molality of the solution is:

= \dfrac{61.6 \ g \times \dfrac{1 \ mol \ NH_4Cl}{53.5 \ g} }{1150 \ g \times \dfrac{1 \ kg}{1000 \g }}

Molar depression constant of solvent X, K_f = 4.82 ^0 \ C/m

Hence, using the elevation in boiling point;

the Vant'Hoff factor i = \dfrac{\Delta T_f}{k_f \times m}

i = \dfrac{7.3 \ ^0 \ C}{4.82 ^0 \ C/m \times 1.00 \ m}

\mathbf {i = 1.51 }

3 0
3 years ago
(a) The student dissolves the entire impure sample of CuSO4(s) in enough distilled water to make 100.mL of solution. Then the st
Talja [164]

Answer:

Explanation:

Given parameters :

Volume of solution  = 100mL

Absorbance of solution  = 0.30

Unknown:

Concentration of CuSO₄ in the solution = ?

Solution:

There is relationship between the absorbance and concentration of a solution. They are directly proportional to one another.

A graph of absorbance against concentration gives a value of 0.15M at an absorbance of 0.30.

The concentration is 0.15M

Also, we can use:  Beer-Lambert's law;

                    A  = ε mC l

where εm is the molar extinction coefficient

             C is the concentration

             l is the path length

Since the εm is not given and assuming path length is 1;

         Then we solve for the concentration.

3 0
3 years ago
Balance the equation ___ CaCO3 -&gt; ____ CaO + ____ CO2
Degger [83]

Answer:

CaCO3 -> CaO + CO2

Explanation:

Woahhhh, did you balance it yourself just then?

3 0
3 years ago
What did john dalton state in his atomic theory
ira [324]
<span>Although two centuries old, Dalton's atomic theory remains valid in modern chemical thought. 1) All matter is made of atoms. Atoms are indivisible and indestructible. 3) Compounds are formed by a combination of two or more different kinds of atoms.</span>
4 0
3 years ago
Read 2 more answers
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