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aliina [53]
3 years ago
8

Does solubility have any unit? Answer properly​

Chemistry
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

Water solubility is a measure of the amount of chemical substance that can dissolve in water at a specific temperature. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million). You can often find it in the section 9 of a safety data sheet (SDS).

Explanation:

n200080 [17]3 years ago
4 0
Water solubility is a measure of the amount of chemical substance that can dissolve in water at a specific temperature. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million). You can often find it in the section 9 of a safety data sheet (SDS
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8.0 mol AgNO3 reacts with 5.0 mol Zn in
Yakvenalex [24]

Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgNO₃: 2 moles
  • Zn: 1 mole
  • Ag: 2 moles
  • Zn(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}

<u><em>amount of moles of AgNO₃= 10 moles </em></u>

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

<h3>Moles of Ag formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}

<u><em>amount of moles of Ag= 8 moles</em></u>

Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

#SPJ1

4 0
2 years ago
Formula for Hydrocloric Acid.
Elden [556K]
HCl is the formula for hydrocloric acid
6 0
3 years ago
Example of electrovalent bond​
olchik [2.2K]

Explanation:

<h3>MgCl2, CaCl2, MgO, Na2S, CaH2, AlF3, NaH, KH, K2O, KI, RbCl, NaBr, CaH2 etc.</h3>

<h2>hope it helps.</h2><h2>stay safe healthy and happy..</h2>
4 0
3 years ago
Read 2 more answers
How would you properly measure the mass of a liquid
MArishka [77]
You can consider the density of the water. Thus, in order to properly measure the mass of a liquid, we can first get the volume and density of the liquid material or substance. We can firstly utilize the formula to get the mass from deriving the set formula of density to mass: Since density is mass over the volume, <span><span>
1.  </span>D=m/v</span> <span><span>
2.  </span>We can transmute the formula to m = dv</span>
<span><span>3.  </span>Mass is density times the volume</span>



4 0
3 years ago
. What is the molarity of a solution that was prepared by dissolving 80.0 g of CaCl2 (molar mass = 111.1 g/mol) in enough water
garri49 [273]

Explanation:

Molarity = mol/L or g/L

Data:

Mass>80.0g

Mr of CaCl2>111.1g/mol

V>500mL

Convert mL to Litres;. mole=g/Mr

1L=1000mL. =80g/111.1g/mol

x=500mL. =0.720072007mol

x=0.5L

Molarity= mole/volume

=0.720072007mol/0.5L

=1.440144014mol/L

=1.4401mol/L

Hope this helps. Depending on the question you can also find it in g/L but mol/L is safer.

7 0
3 years ago
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