Answer:
677.76 g of oxygen needed.
Explanation:
Given data:
Mass of glucose = 635.2 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
Number of moles of glucose:
Number of moles = mass/ molar mass
Number of moles = 635.2 g / 180.156 g/mol
Number of moles = 3.53 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
3.53 : 6×3.53 = 21.18 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 21.18 g × 32 g/mol
Mass = 677.76 g
Answer:
it is ammonia nitro oxide
Answer: 2. Density
3. Physical Property
4. Chemical Change
5. states of matter
Explanation: Density is referred as mass per unit volume. Physical properties are observable characteristics of an object. An new formation of a substance in a chemical reaction is a chemical change. And solids, liquids, and gases are states of matter.
Use the Ideal Gas Law to find the moles of gas first.
Be sure to convert T from Celsius to Kelvin by adding 273.
Also I prefer to deal with pressure in atm rather than mmHg, so divide the pressure by 760 to get it in atm.
PV = nRT —> n = PV/RT
P = 547 mmHg = 547/760 atm = 0.720 atm
V = 1.90 L
T = 33°C = 33 + 273 K = 306 K
R = 0.08206 L atm / mol K
n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas
Now divide grams by mol to get the molecular weight.
3.42 g / 0.0545 mol = 62.8 g/mol
Answer: xx xx
xxOxxCxxSxx
Explanation:
Sorry for the structure, but since Oxygen and Sulfur belong to group of six they want to share two electrons. Carbon belonging to group four wants to share 4 since its valence shell has four electrons.
Therefore the resulting Lewis structure is linear (like carbon dioxide) with two pairs of lone pairs in each O and S atoms and 0 lone pairs in carbon and two double bond.
