Answer:
The required mass is 22.04 g
Explanation:
We know,
Atomic mass of Co= 58g.
Now,
1 mole Co = 58 g
∴ 0.38 mole Co= (58 X 0.38) g
= 22.04 g
So, the required mass is 22.04 g
D because 0 is always ignorant in significant figures. hope that helps:)
There is 55 neutrons in Cesium-130.
D 42.2 L/mol I’s is it I got it correct
It would be 6 because of the elements