All categories

4 years ago

How do you convert moles of a compound to mass?

Chemistry

1 answer:

laiz [17]4 years ago

3 0

Answer:

Divide the mass of the compound in grams by the molar mass you just calculated. The answer is the number of moles of that mass of compound

Explanation:

You might be interested in

Aspirin synthesis involves the addition of an acetyl group to salicylic acid in a condensation reaction with an alcohol. The ace

BARSIC [14]

Answer:

The correct appropriate will be Option 1 (Acid anhydrides are less stable than esters so the equilibrium favors the ester product.)

Explanation:

Acid anhydride, instead of just a carboxyl group, is typically favored for esterification. The predominant theory would be that Anhydride acid is somewhat more volatile than acid. This is favored equilibrium changes more toward the right of the whole ester structure.
Extremely responsive than carboxylic acid become acid anhydride as well as acyl chloride. Thus, for esterification, individuals were most favored.

The other options offered are not relevant to something like the scenario presented. So, the solution here is just the right one.

3 0

3 years ago

Which of these expressions are correct variations of the Combined Gas Law?

mafiozo [28]

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

PV = nRT

and then;

$\frac{P_{1}V_{1} }{T_{1} }$ = $\frac{P_{2}V_{2} }{T_{2} }$

If we cross multiply;

P₁V₁T₂ = P₂V₂T₁

So;

T₁ = $T_{2} \frac{P_{1}V_{1} }{P_{2} V_{2} }$

Also;

V₂ = $V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }$

So from the choices both are correct

3 0

3 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

3 years ago

Anabelle has noticed that her strawberry plants haven't produced any strawberries yet this year.

marusya05 [52]

Answer:0.260

Explanation:

4 0

4 years ago

Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de

nignag [31]

Answer:

$\%m/m=14\%$

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

$[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}$

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

$[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14$

Which is also the by-mass fraction and in percent it turns out:

$\%m/m=0.14*100\%\\\\\%m/m=14\%$

Best regards!

6 0

3 years ago

How do you convert moles of a compound to mass?​

How do you convert moles of a compound to mass?