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Umnica [9.8K]
3 years ago
9

Will award most brainliest need help pls (due today)

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

m∠A = 24°

Step-by-step explanation:

m∠A = m∠B

3x-12 = 2x

-2x.      -2x

x-12 = 0

x = 12

3(12)-12 = 24

2(12) = 24

11 (12) = 132

132 + 24 +24 = 180

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9W + W^2 + 20 using the foil method
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nadezda [96]

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Step-by-step explanation:

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A utility (such as a power company) which controls all services in a designated area is called a
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These are the choices I found on the internet:
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B) cartel.
C) natural monopoly.
D) devised oligopoly.

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2 years ago
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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m

To find:

\textrm{final velocity} = v = ?

Solution:

As we know the third equation of motion is represented as

v^{2} = u^{2} + 2\times a\times s\\

Substituting the values u, a and s in the above equation we get

v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\

v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s

7 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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